I need help with this.

Which of these daily activities helps build a stronger body?

Whitepunk [10]

Answer:

riding a bicycle to and from school each day

Step-by-step explanation:

As this involves the constant application of force from the leg muscles, this will help to build a stronger body.

8 0

2 years ago

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30 students in a class went on a trip to the other side of the city. There were 4 vans for the

torisob [31]

Answer:

6

Step-by-step explanation:

30-6=24

(6 people walked which means they are not included in the people fitting on the busses)

24/4=6

(from there you need to divide by 4 to tell how many were on each bus.)

3 0

3 years ago

Help me please!! I forgot how to do it!

LuckyWell [14K]

Answer:

i think the answer is 79

Step-by-step explanation:

im not really sure,

3 0

3 years ago

During a stretch of 5 games, Stephen Curry averaged 42 points per game. In his first 4 games he scored 45, 48, 32, and 40 points

makkiz [27]

First, I will add up the know amount of points Chef Curry scored
45 + 48 + 32 + 40 = 165
To find the mean, add up all the numbers and divide that by how many values you had
I know 210 / 5 = 42, so I will subtract:
210 - 165 = 45
Cheer Curry scored 45 points
Brainliest?
:3

7 0

4 years ago

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The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08

kvv77 [185]

Answer:

a) 44.93% probability that there are no surface flaws in an auto's interior

b) 0.03% probability that none of the 10 cars has any surface flaws

c) 0.44% probability that at most 1 car has any surface flaws

Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So $\mu = 10*0.08 = 0.8$

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493$

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a $p = 0.4493$ probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.