Answer:
3
Explanation:
For an ideal ramp, M.A/V.R = 1 where M.A = mechanical advantage and V.R = velocity ratio.
Now, V.R = distance moved by effort, d'/distance moved by load, d = d'/d
Now, d' = 3 m and d = 1 m.
So, V.R = d'/d = 3 m/1 m = 3
From M.A/V.R = 1
M.A = V.R = 3
So, the ideal mechanical advantage of the ramp M.A = 3
Answer:
0.70 J/g.°C
Explanation:
Step 1: Given data
- Mass of graphite (m): 402 g
- Heat absorbed (Q): 1136 J
- Initial temperature: 26°C
- Specific heat of graphite (c): ?
Step 2: Calculate the specific heat of graphite
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 1136 J / 402 g × (30°C - 26°C)
c = 0.70 J/g.°C
<span>Isotopes are atoms of the same element with the same
number of protons and same number of electrons but with <span>different number of neutrons. They differ in the number of neutrons that
is why they also differ in mass numbers. Since they have the same number of
protons, they have the same atomic number.
For instance, when the nucleus of the isotope with a 68.926 amu, there are 30
protons and 39 neutrons in the nucleus. The best example for this is Zn (zinc-69
isotope) and Ga (gallium-69 isotope) which has 68.926 amu and 68.925 amu
respectively. </span></span>
Answer:
Partial pressure N₂ . (Partial pressure H₂O)² / (Partial pressure H₂)² . (Partial pressure NO)² = Kp
Explanation:
The reaction is:
2NO + 2H₂ → N₂ + 2H₂O
The expression for Kp (pressure equilibrium constant) would be:
Partial pressure N₂ . (Partial pressure H₂O)² / (Partial pressure H₂)² . (Partial pressure NO)²
There is another expression for Kp, where you work with Kc (equilibrium constant)
Kp = Kc (R.T)^Δn
where R is the Ideal Gases constant
T° is absolute temperature
Δn = moles of gases formed - moles of gases, I had initially
