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liq [111]
3 years ago
15

One office building contains only incandescent lights. The building next door contains only fluorescent lights. Predict which bu

ilding has higher energy bills. Explain your answer.
Chemistry
1 answer:
denpristay [2]3 years ago
7 0
The building with incandescent light bulbs would have higher energy bills because less than 10% of the bulb is used for light while the rest is given off as heat. Fluorescent light bulbs use ¼ as much energy and provide the same amount of light.
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A rectangular solid is 2.3 cm wide, 12.2 mm long and 0.75 inch thick. What is the volume of the piece?
Step2247 [10]
V=abc

a = 2,3cm
b=12,2mm = 1,22cm
c = 0,75inch = 1,905cm

V = 2,3cm*1,22cm*1,905cm ≈ 5,35cm³
5 0
3 years ago
A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
3 years ago
Suppose you are presented with a clear solution of sodium thiosulfate, Na2S2O3 . How could you determine whether the solution is
navik [9.2K]

Explanation:

A solution is said to saturated when it cannot dissolve any extra solute in it. The extra solute put remains undissolved.

A solution is said to unsaturated, when the concentration of solute is less as compared to solubility of the solution it is said to be unsaturated.

A solution is said to be super saturated when it contains more of the solute than the solvent  can dissolve under normal conditions is called super saturated.

5 0
3 years ago
Study of gene structure and function
gregori [183]

I believe the answer would be b

7 0
3 years ago
he mineral rhodochrosite [manganese(II) carbonate, MnCO3] is a commercially important source of manganese. Write a half-reaction
valina [46]

Answer:

MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

Explanation:

Half reaction:MnCO_{3}\rightarrow MnO_{2}

(1)CO_{3} balance: MnCO_{3}\rightarrow MnO_{2}+HCO_{3}^{-}

(2)H and O balance in acidic medium:MnCO_{3}+2H_{2}O\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

(3) charge balance:MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

Hence balanced half-reaction:MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

7 0
3 years ago
Read 2 more answers
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