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Zepler [3.9K]
3 years ago
10

What is the maximum height for -16t^2+96t+63

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

h(3) =  207 feet

Step-by-step explanation:

what is the maximum height for -16t^2+96t+63

h(t) = -16t^2+96t+63

We see  max height at the vertex of this parabolic function

x = -96/2*(-16)  = 3 seconds

h(3) = -16*3*3  + 96*3  + 63

h(3) =  -144  + 288 + 63

h(3) =  207 feet

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