3 years ago

What is the maximum height for -16t^2+96t+63

Mathematics

1 answer:

azamat3 years ago

4 0

Answer:

h(3) = 207 feet

Step-by-step explanation:

what is the maximum height for -16t^2+96t+63

h(t) = -16t^2+96t+63

We see max height at the vertex of this parabolic function

x = -96/2*(-16) = 3 seconds

h(3) = -16*3*3 + 96*3 + 63

h(3) = -144 + 288 + 63

h(3) = 207 feet

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