Question

Write an equation in point -slope form for the line through the given point that has the given slope.

Answer 1

Answer:

1. y+4=6(x-3)

y +4=6x-18

2. y + 2 = -5/3(x-4)

y+2=-5/3x-(-5/3(-4))

3. y=4/5x - 8/5

4. y+7=-3/2x-3

5. y-4=x

6. y+8=-3x +15

7. y-2= 0x

8. y+8= -1/5x-1/5

9. y-1= 2/3x-4

Answer 2

Answer:

1. y=6x-22

Step-by-step explanation:

point-slope form equation : y=mx+b

1. (3, -4) m=6

Sub the numbers is

y=-4 / x=3 / m = 6

-4=6*3+b

-4=18+b

b=-22

So your equation would be y=6x-22

2. (4, 2) m=-5/3

sub the numbers into the equation

y=2 / x=4 / m= 5/3

2=4*5/3+b

2=20/3+b

b=8 2/3

so the equation would be

y=-5/3x+8 2/3

3. (0,2) m=4/5

sub the numbers into the equation

2=0*4/5+b

b=2

so the equation would be

y=4/5x+2

4. (-2, -7) -3/2

sub the numbers into the equation

-7=-3/2*-2+b

b=-10

so the equation would be

y= 3/2x-10

5. (4,0) 1

sub the numbers into the equation

0=1*4+b

b=-4

so the equation would be

y=x-4

6. (5,-8) -3

sub the numbers into the equation

-8=5*-3+b

-8=-15+b

b=7

so the equation would be

y=-3x+7

7. (-5, 2) 0

sub the numbers into the equation

2=-5*0+b

b=2

so the equation would be

y=2

8. (1, -8) -1/5

sub the numbers in

-8=1*-1/5+b

b= 7 3/5

so the equation would be

y=-1/5x + 7 3/5

9. (-6,1) 2/3

sub the number in

1=2/3*6+b

b=-3

so the equation would be

y=2/3x-3