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docker41 [41]
2 years ago
6

A stockbroker estimates that at the end of the year, there is a 40% chance a stock will be worth $50,

Mathematics
1 answer:
nadya68 [22]2 years ago
6 0

The expected value  that  this broker assign to this stock's end-of-the-year price is $58.50.

Using this formula

Expected value=Stock worth at $50+ Stock worth at $60+ Stock worth at $70

Where:

Stock worth at $50=40% chance

Stock worth at $60=35% chance

Stock worth at $70=25% chance

Let plug in the formula

Expected value=(40%×$50)+($35%×$60)+($25%×$70)

Expected value=$20+$21+$17.5

Expected value=$58.50

Inconclusion the expected value  that  this broker assign to this stock's end-of-the-year price is $58.50.

Learn more here:

brainly.com/question/12834805

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The length s(t)s(t)s, (, t, )of the side of the base of a square prism is decreasing at a rate of 777 kilometers per minute and
gavmur [86]

Answer:

\frac{dA_{s}}{dt} = -148\,\frac{km^{2}}{min}

Step-by-step explanation:

The surface area of the square prism is obtained by using the following formula:

A_{s} (t) = 4\cdot l(t)\cdot h(t) + 2\cdot [l(t)]^{2}

The rate of change of the surface area can be found by deriving the function with respect to time:

\frac{dA_{s}}{dt} = 4\cdot [h(t)\cdot \frac{dl}{dt} + l(t)\cdot \frac{dh}{dt}] + 2\cdot l(t)\cdot \frac{dl}{dt}

Known variables are summarized below:

h(t) = 9\,km

l(t) = 4\,km

\frac{dh}{dt} = 10\,\frac{km}{min}

\frac{dl}{dt} = -7\,\frac{km}{min}

The rate of change is:

\frac{dA_{s}}{dt} = 4\cdot [(9\,km)\cdot (-7\,\frac{km}{min} )+(4\,km)\cdot (10\,\frac{km}{min} )] + 2\cdot (4\,km)\cdot (-7\,\frac{km}{min} )

\frac{dA_{s}}{dt} = -148\,\frac{km^{2}}{min}

3 0
3 years ago
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A circle has a radius of 6 cm. Find its exact circumference.
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The radius of circle is r = 6 cm.

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C=2\pi r

For exact circumference take pi = 3.14.

Substitute 6 for r in the formula to determine the circumference of circle.

\begin{gathered} C=2\pi\cdot6 \\ =12\pi \\ =37.68 \end{gathered}

So exact circumference of circle is 37.68 or 12 pi .

8 0
1 year ago
(8v)^-1 writer with positive exponent and then simplify.
IgorLugansk [536]
(8v)^{-1}= \cfrac{1}{8v^1} = \cfrac{1}{8v}
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