Answer is:
a) 32
b) 59
Both are arithmetic sequences
Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
To begin with, let's establish that ( x ) can equal to any number from 0 to 9.
Meaning, that ( x ) is equal to one of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.
Now that we know which values ( x ) can equal to, we will simply substitute each of the numbers as potential values of ( x ) into the six-digit number and divide it by 27 to see if it is a multiple of 27.
If X = 0
= 63X904 / 27
= 630904 / 27
= Not a whole number
Therefore, X is not equal to 0.
If X = 1
= 63X904 / 27
= 631904 / 27
= Not a whole number
Therefore, X is not equal to 1.
If X = 2
= 63X904 / 27
= 632904 / 27
= Not a whole number
Therefore, X is not equal to 2.
If X = 3
= 63X904 / 27
= 633904 / 27
= Not a whole number
Therefore, X is not equal to 3.
If X = 4
= 63X904 / 27
= 634904 / 27
= Not a whole number
Therefore, X is not equal to 4.
If X = 5
= 63X904 / 27
= 635904 / 27
= 23552
ANSWER:
Therefore, the answer is:
X = 23, 552
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Thank you <3
=(9(1/3))^2+2+4/7
=(3^2)+2+4/7
=(9)+2+4/7
=11+4/7
=81/7
Answer:
$0.995
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