Let m=1/3 and n=4/7.
1 answer:
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Answer:
first option
Step-by-step explanation:
Given
f(x) = ← factorise the numerator
= ← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x =
There is a zero at ( , 0 )
Thus
discontinuity at (- 4, - 11 ), zero at ( , 0 )
(- 2, - 3) is a solution to the given system of equations.
Answer: Option D
<u>Step-by-step explanation:</u>
Given equation are not presented in proper format. So, let assume the given system of are as below,
2 x - y = -1
2 x -4 y = 8
Now, subtract the second equation from the first, we get
(2 x - y) -(2 x - 4 y) = -1 -8
3 y = -9
y = -3 (obtained this when divide by 3)
Substituting y = - 3 into the first equation, we get
2 x - (-3) = - 1
2 x = - 1 + 3
x = - 2 (obtained when divide by 2)
Now, the answer is (x, y) = (- 2, - 3)
