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3 years ago

Hi, can I please have help with this question and how to do it?

Mathematics

2 answers:

Sati [7]3 years ago

8 0

Do L times W times H or length width and height hope this helps

Marysya12 [62]3 years ago

4 0

Answer:

Volume is LxWxH

Step-by-step explanation:

Multiply 50,75, and 50

Your answer will be 187,500 A

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Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

5 0

3 years ago

Which number are greater then 0.3?

Lorico [155]

0.39,0.4. I got these answers because 0.39 has an extra digit the 0.3 so 0.3 becomes 0.30 and 0.39 is bigger than it. 0.4 is greater than 0.3 because the 4 in 0.4 is greater than 0.3. Hope This Helped :D

3 0

3 years ago

The amount of money in a savings account after t years is represented by the function f(t)=500(1.015)t.

Sauron [17]

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
f(t)=\stackrel{\stackrel{I}{\downarrow }}{500}(1.015)^t$

5 0

3 years ago

Read 2 more answers

Which statement is true about this data set? {43, 46, 48, 57, 42, 47, 48, 44, 46, 45, 48}

vfiekz [6]

Answer: D) 57

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Applying the concepts. Need help finding the value.

luda_lava [24]

we can use formula

$log_ab=\frac{ln(b)}{ln(a)}$

$log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(3)}{ln(2)}*\frac{ln(4)}{ln(3)}*\frac{ln(5)}{ln(4)}*\frac{ln(6)}{ln(5)}*\frac{ln(7)}{ln(6)}*\frac{ln(8)}{ln(7)}$