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worty [1.4K]
3 years ago
13

What is the solution of (8x-8)^3/2=64Edit; the answer is x=3

Mathematics
1 answer:
Talja [164]3 years ago
6 0

I guess since you have the correct answer there that you need to know how to get it. Start by rewriting that exponent as a radical. It would look like this: \sqrt{(8x-8)^3}=64. The first step is to undo that square root by squaring both sides. That will give you this: (8x-8)^3=4096. Next we have to undo that cubing by taking the cubed root of both sides, leaving us with this: 8x-8=16. We add 8 to both sides to get 8x = 24 and x = 3.

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What is the solution to 9x−6<21?
Alisiya [41]

Answer:

x > 3

Step-by-step explanation:

1) Add 6 to both sides.

9x > 21 + 6

2) Simplify 21 + 6 to 27.

9x > 27

3) Divide both sides by 9.

x >  \frac{27}{9}

4) Simplify 27/9 to 3.

x > 3

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>option</u><u> </u><u>B</u><u>.</u><u> </u><u>x</u><u> </u><u>></u><u> </u><u>3</u>.

7 0
3 years ago
What property does the statement show? (4x8)x3=(8x4)x3
8090 [49]
Why not? Because every math system you've ever worked with has obeyed these properties! You have never dealt with a system where a×b did not in fact equal b×a, for instance, or where (a×b)×c did not equal a×(b×c). Which is why the properties probably seem somewhat pointless to you. Don't worry about their "relevance" for now; just make sure you can keep the properties straight so you can pass the next test. The lesson below explains how I kept track of the properties.
6 0
3 years ago
Alguien sabe hacer alguno de ellos XFAVOR D;
iris [78.8K]

Answer:

english please...

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
P(1, 10)and Q(7,4) are the endpoints of a line segment. What is the midpoint M of that line segment
melamori03 [73]

Answer:

(4, 7)

Step-by-step explanation:

The midpoint formula is (((x1 + x2)/2), ((y1+y2)/2)))

x1 +x2 = 1 +7 = 8

8/2 = 4

y1 + y2 = 10 + 4 = 14

14/2 = 7

(4, 7) is the midpoint

6 0
4 years ago
Read 2 more answers
Suppose you are asked to take a sample of men and women in order to measure their emotional IQ. The emotional IQ scale that you
yan [13]

Answer:

The 99% confidence interval for the scores of men is (64.406,75.594).

The 99% confidence interval for the scores of women is (73.609,90.391).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution will be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.797.

For men:

Standard deviation of 10.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.797\frac{10}{\sqrt{25}} = 5.594

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 70 - 5.594 = 64.406

The upper end of the interval is the sample mean added to M. So it is 70 + 5.594 = 75.594

The 99% confidence interval for the scores of men is (64.406,75.594).

For women:

Standard deviation of 15.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.797\frac{15}{\sqrt{25}} = 8.391

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 82 - 8.391 = 73.609

The upper end of the interval is the sample mean added to M. So it is 82 + 8.391 = 90.391

The 99% confidence interval for the scores of women is (73.609,90.391).

4 0
3 years ago
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