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3 years ago

How to find the area of a regular polygon?

2 answers:

4 0

To find the regular follow this formula ; area = 1/2 x perimeter x apothem. Which means ... perimeter = the sum of lengths of the all sides

olchik [2.2K]3 years ago

4 0

To find the area of a regular polygon, we need to use the formula A = (1/2)(apothem)(perimeter). The apothem is the radius of the polygon.

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Write as a Improper fraction

Likurg_2 [28]

38/9
46/7
44/5
11/4
19/2
11/6
23/3
41/8
52/7
34/5

8 0

3 years ago

Read 2 more answers

Cassie bought a pair of loafers for $29.95. Tights were on sale for 3 pairs for $10.00. She gave the clerk $60.00. How much chan

monitta

Answer:

$20.05 is Cassie's change

Step-by-step explanation:

60.00-29.95=30.05

30.05-10=20.05

5 0

3 years ago

The Greek alphabet contains 24 letters. How many fraternity names with Greek letters can be formed if each fraternity name conta

ankoles [38]

For the first letter we have 24 choices. Since letters can't repeat the second letter has 23 choices (24 minus 1 that was used for the first slot) and the third has 22 (24 minus one for the first slot and one for the second slot).

The total number of combinations is thus: 24 x 23 x 22= 12,144

4 0

3 years ago

Read 2 more answers

e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv

Naddika [18.5K]

Answer:

The answer is $\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$

Step-by-step explanation:

Remember that a reflexive relation $R\subset \mathcal{P}(X)$ , where $\mathcal{P}(X)$ is the power set of $X$ , is one which conteins the ordered pairs of the form $(a,a)$ , for $a\in X$ .

So, As the reflexive and transitive closure of $R$ (that we will denote by $\overline{R}$ ) is in particular reflexive, we must add to $R$ the elements $\{(1,1) , (2,2),(3,3),(4,4) \}$

A transitive relation $R$ is one in which if the pair $(a,b)$ and the pair $(b,c)$ are in there, then the pair $(a,c)$ must be there too.

So, to complete the relation $R$ to be reflexive and transitive we must add the pair $(1,3)$ (because $(1,2),(2,3)$ are in $R$ ), the pair $(2,4)$ , and the pair $(1,4)$ because we added the pair $(2,4)$ .

Therfore we have that $\overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$ .

6 0

3 years ago

BAD is congruent to BCD by <br> the

scoundrel [369]

AB is congruent to BC

6 0

3 years ago