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d1i1m1o1n [39]
3 years ago
8

How to find the area of a regular polygon?

Mathematics
2 answers:
vaieri [72.5K]3 years ago
4 0
To find the regular follow this formula ; area = 1/2 x perimeter x apothem. Which means ... perimeter = the sum of lengths of the all sides
olchik [2.2K]3 years ago
4 0
To find the area of a regular polygon, we need to use the formula A = (1/2)(apothem)(perimeter). The apothem is the radius of the polygon.
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What is the value of<br> 4.2(46 – 65)
mars1129 [50]

Answer:

-79.8

Step-by-step explanation:

plug into a calculator, making sure to keep perenthesis in the correct places

4 0
3 years ago
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Determine the area of a,b and c. a to b=7.5 inches a to d= 16.8 inches
Alex777 [14]
The area would be 63.The steps to how I got that anwser:
1.] Write your formula
A=bh
    ----
      2
2.]Begin by plugging in your measurements
A=7.5 times 16.8
     -------------------
             2
3.]Multiply the top two numbers together
A=126
     -----
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4.]Divide to get your final anwser
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3 0
4 years ago
In the diagram below is a regular pentagon ABCDE, side EB is drawn.
Kaylis [27]

Answer:

BEA is 36° and BED is 72° therefore DAEB is 108°

8 0
3 years ago
Find the exact value of cos(-7pi/4 radian).
nata0808 [166]
<span>cos<span>[<span><span>7pi/</span>4</span>]</span></span>=<span>cos<span>(2pi−pi<span>4</span>)
</span></span>               =<span>cos<span>(−pi/<span>4</span>)
</span></span>               =<span>cos<span>(pi<span>4</span>)
</span></span>               =<span><span><span>√2/</span>2</span></span>
8 0
4 years ago
Read 2 more answers
Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probabili
Gemiola [76]

Answer:

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851</em>

Step-by-step explanation:

<u>step(i)</u>:-

<em>Let 'X' be the random Normal variable</em>

<em>mean of the Population = 365.45</em>

<em>Standard deviation of the population = 4.9 cm</em>

<em>Let X₁ =  360</em>

<em></em>Z= \frac{x-mean}{S.D}= \frac{360-365.45}{4.9}<em></em>

<em>Z₁ = -1.112</em>

<em>Let X₂ =  370</em>

<em></em>Z= \frac{x-mean}{S.D}= \frac{370-365.45}{4.9}<em></em>

<em>Z₂ = 0.911</em>

<u><em>Step(ii</em></u><em>):-</em>

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm</em>

<em>                   P(x₁≤x≤x₂) =    P(z₁≤Z≤z₂) </em>

<em>                P(360 ≤X≤370)   =    P(-1.11≤Z≤0.911)</em>

<em>                                      =    P(Z≤0.911)-P(Z≤-1.11)</em>

<em>                                      =   0.5 +A(0.911) - (0.5-A(1.11)</em>

<em>                                        =    0.5 +A(0.911) - 0.5+A(1.11)</em>

<em>                                       =     A(0.911) + A(1.11)</em>

<em>                                     =    0.3186 + 0.3665</em>

<em>                                      = 0.6851</em>

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851</em>

<em></em>

<em></em>

5 0
3 years ago
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