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4 years ago

What is the answer to 8x -2=3x + 12.25

Mathematics

1 answer:

earnstyle [38]4 years ago

5 0

X=2.85
it simplifies to 5x=14.25, and then 14.25/5=2.85

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Which of the following statements is true according to the associative property of multiplication?

goldenfox [79]

(5x4) x 20 = 5 x (4 x 20)

6 0

4 years ago

Read 2 more answers

One night, it is 24LaTeX: ^\circ

tatuchka [14]

Answer:

$T^\circ = -12^\circ$

Step-by-step explanation:

Given

Represent the temperature in Tucson with T and that in Minneapolis with M.

From the first statement, we have:

$T^\circ = M^\circ - 24^\circ$

From the second, we have:

$T^\circ = -M^\circ$ or $M^\circ = -T^\circ$ --- i.e. both are opposite numbers

Required

Find T

To calculate T, substitute -T for M in $T^\circ = M^\circ - 24^\circ$

This gives:

$T^\circ = -T^\circ - 24^\circ$

Collect Like Terms

$T^\circ +T^\circ =- 24^\circ$

$2T^\circ =- 24^\circ$

Make T the subject

$T^\circ =- 24^\circ/2$

$T^\circ = -12^\circ$

Hence, the temperature in Tucson is $-12^\circ$

8 0

3 years ago

Can someone please help

Kitty [74]

Answer:

ez, all you need to do is find the area of the rectangle by itself so 3x9 is 27, cuz its formula is bxh then u need to find the area of the triangle so 3x3 which is 9 and divde by 2 which is 4.5 and 27-4.5 is 22.5 so thats ur answer.

Step-by-step explanation:

6 0

3 years ago

A triangular pyramid has a base with an area of 21.8 square meters, and lateral faces with bases of 7.1 meters and heights of 9

Ymorist [56]

Answer:

Step-by-step explanation:

A triangular pyramid has a base with an area of 21.8 square meters, and lateral faces with bases of 7.1 meters and heights of 9 meters. Enter an expression that can be used to find the surface area of the triangular pyramid.

The expression is written as:

Surface Area = Area of the base + 1/2( Perimeter × Slant height)

8 0

3 years ago

Find the slope of the curve below at the given points. Sketch the curve along with its tangents at these points. R = sin 2 theta

mr Goodwill [35]

Answer:

<u> </u><u>-1 </u>

Step-by-step explanation:

Given that:

r = sin 2θ , θ = ± π/4 , ± 3π/4

Recall that:

x = r cosθ

y = r sinθ

The differential of y with respect to x

$\dfrac{dy}{dx} = \dfrac{\dfrac{dy}{d \theta}}{\dfrac{dx}{d \theta}}$

$\dfrac{dy}{dx} =\dfrac{\dfrac{dy}{d \theta}}{\dfrac{dx}{d \theta}} = \dfrac{ r cos \theta + sin \theta* \dfrac{dr}{d \theta} } {\dfrac{dr}{d \theta} *cos \theta- sin \theta \ r}$

at θ = π/4 , r = sin π/2

r = 1

$\dfrac{dy}{dx} = \dfrac{ r cos \theta + 2 cos (2 \theta)*sin \ \theta } {2 \ cos (2 \theta) *cos \theta- sin 2 \theta * sin \theta}$

where;

θ = π/4

$\dfrac{dy}{dx} = \dfrac{ 1 \times cos (\dfrac{\pi}{4}) + 2 cos (\dfrac{\pi}{2})*sin (\dfrac{\pi}{4}) } {2 \ cos (\dfrac{\pi}{2})*cos (\dfrac{\pi}{4})- sin (\dfrac{\pi}{2}) * sin (\dfrac{\pi}{4})}$

$\dfrac{dy}{dx} = \dfrac{\dfrac{1}{\sqrt{2}}+0 }{0-1 * \dfrac{1}{\sqrt{2}}}$

$\dfrac{dy}{dx} = \dfrac{\dfrac{1}{\sqrt{2}} }{- \dfrac{1}{\sqrt{2}}}$

$\mathbf{\dfrac{dy}{dx} =-1}$

slope of the curve (dy/dx) at theta(θ) = pi/4 is -1

7 0

3 years ago