This kinda took a lot of effort but hope it helps
9514 1404 393
Answer:
- 3n+6 (n = smallest)
- 3n (n = middle)
Step-by-step explanation:
The usual method for doing this is to let n represent the smallest one. Then the three integers are ...
n, n+2, and n+4
and their sum is ...
(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)
_____
Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:
(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)
Option A: >
Solution:
Given a triangle GHJ.
The line GH is perpendicular to line HJ.
This means the triangle is a right angled triangle.
In ΔGHJ, GH is the base of the triangle and
HJ is a height of the triangle.
Then the third side must be the hypotenuse of the right triangle.
We know that by the Pythagoras theorem,


This clearly shows that the hypotenuse is greater than the height.
⇒ GJ > HJ
Option A: > is the correct answer.
If line GH is perpendicular to line HJ, then GJ is > HJ.
Your answer will be letter c