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3 years ago

Graphing functions f(x)=x^2-6x-27/x+3

1 answer:

5 0

Funny, this looks like a complex graph, until you realize that the numerator can be written like (x+3)(x-9).

So really, this is a straight line f(x) = x-9.

But wait, there's a catch. x≠3, because that would divide by zero. So in your straight line, you have to draw a "hole" at (3,6)

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The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane. If f(x) is an odd function

sashaice [31]

Answer a one i did this before

4 0

3 years ago

Find the total surface area of the<br> following square pyramid:<br> 6 cm<br> 8 cm

Norma-Jean [14]

Answer:

Surface area of square pyramid = $160cm^{2}$

Step-by-step explanation:

Let, b is the length of the base and s is the slant height

According to given condition:

b = 8 cm

s = 6 cm

Find out:

Surface area of square pyramid = ?

Formula:

Surface area of square pyramid = $b^{2} + 2bs$

Solution:

Surface area of square pyramid = $b^{2} + 2bs$

Surface area of square pyramid = $8^{2} + 2(8)(6)$

Surface area of square pyramid = $(64+ 96 ) cm^{2}$

Surface area of square pyramid = $160cm^{2}$

8 0

3 years ago

Which option is an example of a survey?

Mars2501 [29]

Answer:

Having customers fill out a questionnaire about their favorite brand of toothpaste.

5 0

3 years ago

What is the product of the two matrices? Fill in the missing elements of the resulting matrix.

olganol [36]

The product of the given two matrices comes out to be $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Here we are given the 2 matrices as follows-

$\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]$

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

$\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]$

= $\left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]$

= $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Thus, the product of the given two matrices comes out to be $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Learn more about matrices here-

brainly.com/question/13595915

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3 0

1 year ago

There are 8,253 men and 10,327 women at a state university. If 43% of the men are in business and 27% of the women are in busine

fredd [130]

Answer:

68 students

Step-by-step explanation:

Number of men who major in business in the university= 0.43*8253=3548.79

Rounding off we have 3549 students

Number of women who major in business in the university= 0.27*10327=2788.29

Approximately 2789 students

Total students who major in Business= 3549+2789=6338 students

Total students in school= 8253+10327=18580

Probability of getting business major= 6338/18580

Out of 200 students, we expect

$\frac {6338}{18580} \times 200=68.22389666$

Approximately 68 students will be majoring in business

8 0

3 years ago