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balu736 [363]
2 years ago
9

If point d is placed on AC, how will the measure of DAB relate to the measure of CAB?

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

angle DAB will be equal to angle CAB

Step-by-step explanation:

Lostsunrise [7]2 years ago
4 0

angle DAB will be equal to angle CAB

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I need whats in the red rectangle
lorasvet [3.4K]

Answer:

9

Step-by-step explanation:

sqrt(5) + sqrt(405)

sqrt(5) + sqrt( 81*5)

sqrt(5) + sqrt(81) sqrt(5)

sqrt(5) +9 sqrt(5)

10 sqrt(5)

3 0
3 years ago
Which sequence of transformations creates a similar but not congruent triangle?
Vsevolod [243]

Answer:

<h3>             A. Dilation and reflection</h3>

Step-by-step explanation:

There are the same angles in similar triangles but sides not necessarily.

In congruent triangles there are the same angles and the same sides.

Reflection, rotation or translation changes only position of triangle or mirrors it. Doesn't change the size, so the created triangle is congruent.

4 0
3 years ago
What is the image of (4, -12) after a dilation by a scale factor of 1/4 centered at the origin?​
Aleonysh [2.5K]

The answer is (-1,-3)

All you have to do is divide your point by 4, since it is a fraction. if its not then multiply.

5 0
3 years ago
In an experiment, a fair coin is tossed 13 times and the face that appears (H for head or T for tail) for each toss is recorded.
zalisa [80]

Answer:

1) 1 element

2) 13 elements

3) 22 elements

4) 40 elements

Step-by-step explanation:

1) Only one element will have no tails: the event that all the coins are heads.

2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.

3) There are {13 \choose 2} = 78 elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are {11 \choose 2} = 55 possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22

4) We can have:

  • A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
  • One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)

For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)

For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).

This gives us a total of 18+22 = 40 possibilities.

5 0
3 years ago
Carlos is sorting apples for a large orchard.He sorts them into 75 baskets of 30 and 50 baskets of 45.
vekshin1

Answer:

C

Step-by-step explanation:

Because if you have 75 baskets of 30 then you have to multiply 75x30 it is the same thing with 50x45. Hope this helps

7 0
3 years ago
Read 2 more answers
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