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2 years ago

If point d is placed on AC, how will the measure of DAB relate to the measure of CAB?

Mathematics

2 answers:

Karo-lina-s [1.5K]2 years ago

7 0

Answer:

angle DAB will be equal to angle CAB

Step-by-step explanation:

Lostsunrise [7]2 years ago

4 0

angle DAB will be equal to angle CAB

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Find the value of f(2) when f(x) = 4x+2

Sloan [31]

Answer:

the answer is 10

Step-by-step explanation:

f(2) that means the value of x= 2

the substitute x=2 in the 4(2)+2.Replace x with 2

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3 years ago

How many inches are in 200 meters?

4vir4ik [10]

200×39.37=7874
the answer is 7874 in

3 0

3 years ago

Read 2 more answers

if a pound of grapes cost $0.14 in 1960 and the price of grapes increased at the same rate as the CPI from 1960 to 1980 by appro

masya89 [10]

The CPI increased from 29.6 to 82.4.

The rate of increase, is:

82.4/29.6 = 2.78

Now multiply this rate to the $0.14 price of grapes from 1960.

$0.14 x 2.78 = $0.39

Now to get the amount of increase subtract the new price from the original price:

$0.39 - $0.14 = $0.25 increase.

5 0

3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

Marcus bought a booklet of tickets to use at the amusement park. He used 50% of the tickets on rides,

vovangra [49]

No. he used 50% on the rides, and we have to convert the fraction to a percent by dividing 4&1 which equals 0.25, then we multiply that by 100 to get the percentage he used on video games which equals 25%. 50+25= 75% used tickets for both rides and video games. So then we subtract 75 from 100 and get 25% which means he used 25% of the tickets on batting cages. Your answer is no, he used 25% of his tickets on the batting cages.

6 0

3 years ago