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lidiya [134]
3 years ago
6

Ryan has a box of markers. It has 45 markers that are some shade of blue. The blue markers represent 25% of the total markers in

the box. What is the total number of markers in the box?
Mathematics
2 answers:
juin [17]3 years ago
8 0

Answer:

Step-by-step explanation:

nlexa [21]3 years ago
8 0
Ratio time :)

25 percent of 100 = 45 of the unknown number

25/100 = 45/x

Cross multiply
25x = 4500
x = 180

180 total markers in the box
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Plot a point on the coordinate plane to represent each of the ratio values in the table. Time (h) Distance (km) able displaying
Effectus [21]

Answer:

Refer the attached graph.

Step-by-step explanation:

Given : Time (h) Distance (km) able displaying Time in hours in one column and Distance in kilometers in the other. The time column contains 1, 3, 6, and 9. The distance column contains 2, 6, 12, and 18.

To plot : The points on the coordinate plane.

Solution :

Time is independent variable so it is taken on x-axis.

Distance is taken on y-axis.

x    y  

1     2

3    6

6    12

9    18

When we plot these points in the coordinate plane, we get a linear equation.

The linear equation form is y=2x

Refer the attached graph.

4 0
3 years ago
Find the ULE in the triangle below
aivan3 [116]

Where is the triangle?

7 0
3 years ago
The graphs of the quadratic functions f(x) = 6 – 10x2 and g(x) = 8 – (x – 2)2 are provided below. Observe there are TWO lines si
natta225 [31]

Answer:

a) y = 7.74*x + 7.5

b)  y = 1.148*x + 6.036

Step-by-step explanation:

Given:

                                  f(x) = 6 - 10*x^2

                                  g(x) = 8 - (x-2)^2

Find:

(a) The line simultaneously tangent to both graphs having the LARGEST slope has equation

(b) The other line simultaneously tangent to both graphs has equation,

Solution:

- Find the derivatives of the two functions given:

                                f'(x) = -20*x

                                g'(x) = -2*(x-2)

- Since, the derivative of both function depends on the x coordinate. We will choose a point x_o which is common for both the functions f(x) and g(x). Point: ( x_o , g(x_o)) Hence,

                                g'(x_o) = -2*(x_o -2)

- Now compute the gradient of a line tangent to both graphs at point (x_o , g(x_o) ) on g(x) graph and point ( x , f(x) ) on function f(x):

                                m = (g(x_o) - f(x)) / (x_o - x)

                                m = (8 - (x_o-2)^2 - 6 + 10*x^2) / (x_o - x)

                                m = (8 - (x_o^2 - 4*x_o + 4) - 6 + 10*x^2)/(x_o - x)

                                m = ( 8 - x_o^2 + 4*x_o -4 -6 +10*x^2) /(x_o - x)

                                m = ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x)

- Now the gradient of the line computed from a point on each graph m must be equal to the derivatives computed earlier for each function:

                                m = f'(x) = g'(x_o)

- We will develop the first expression:

                                m = f'(x)

                                ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

Eq 1.                          (-2 - x_o^2 + 4*x_o + 10*x^2) = -20*x*x_o + 20*x^2

And,

                              m = g'(x_o)

                              ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

                              -2 - x_o^2 + 4*x_o + 10*x^2 = -2(x_o - 2)(x_o - x)

Eq 2                       -2 - x_o^2 + 4*x_o+ 10*x^2 = -2(x_o^2 - x_o*(x + 2) + 2*x)

- Now subtract the two equations (Eq 1 - Eq 2):

                              -20*x*x_o + 20*x^2 + 2*x_o^2 - 2*x_o*(x + 2) + 4*x = 0

                              -22*x*x_o + 20*x^2 + 2*x_o^2 - 4*x_o + 4*x = 0

- Form factors:       20*x^2 - 20*x*x_o - 2*x*x_o + 2*x_o^2 - 4*x_o + 4*x = 0

                              20*x*(x - x_o) - 2*x_o*(x - x_o) + 4*(x - x_o) = 0

                               (x - x_o)(20*x - 2*x_o + 4) = 0  

                               x = x_o   ,     x_o = 10x + 2    

- For x_o = 10x + 2  ,

                               (g(10*x + 2) - f(x))/(10*x + 2 - x) = -20*x

                                (8 - 100*x^2 - 6 + 10*x^2)/(9*x + 2) = -20*x

                                (-90*x^2 + 2) = -180*x^2 - 40*x

                                90*x^2 + 40*x + 2 = 0  

- Solve the quadratic equation above:

                                 x = -0.0574, -0.387      

- Largest slope is at x = -0.387 where equation of line is:

                                  y - 4.502 = -20*(-0.387)*(x + 0.387)

                                  y = 7.74*x + 7.5          

- Other tangent line:

                                  y - 5.97 = 1.148*(x + 0.0574)

                                  y = 1.148*x + 6.036

6 0
3 years ago
HELP!!!
MakcuM [25]
While since Rajeev is already below the surface by 12.6 ft it’ll be negative (-12.6) and since he went down another 8.7 ft it’ll just be minus since he is still going under, so -12.6-8.7 will be your answer. :)
4 0
3 years ago
Read 2 more answers
Can someone help me pls
VLD [36.1K]

Answer:

-12

Step-by-step explanation:

Since a = -6,we have to multiply 2 and -6,and you get -12 bc we have to put the sign of the bigger digit which is -6 in this problem,so you have to write -12

4 0
2 years ago
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