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4 years ago

What is the answer to eight times something that equals 16

Mathematics

2 answers:

Maurinko [17]4 years ago

5 0

8 times 2 equals to 16

kirza4 [7]4 years ago

5 0

8×Z=16 (Z being the unknown variable)
Z=2 because 16÷8=2

PROOF:
8×2=16
16=16

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Alisiya [41]

Answer:

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Use vertical multiplication to find the product of:

Rom4ik [11]

Answer:

$x^6+x^4+4x^3-2x^2-x+3$

Step-by-step explanation:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

First step multiply your terms in your first expression just to the 1 in the second expression like so:

$x^3+2x+3$

$\times(x^3-x+1)$

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That is, $(x^3+2x+3) \cdot 1=x^3+2x+3$ .

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$x^3+2x+3$

$\times(x^3-x+1)$

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$x^3+2x+3$

$-x^4-2x^2-3x$

We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:

$x^3+2x+3$

$\times(x^3-x+1)$

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$0x^4+x^3+0x^2+2x+3$

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Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us $x^3(x^3+2x+3)=x^6+2x^4+3x^3$ . (I'm going to put this product underneath our other 2 products):

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$0x^4+x^3+0x^2+2x+3$

$-x^4+0x^3-2x^2-3x+0$

$x^6+2x^4+3x^3$

I'm going to again insert some zero placeholders to help me line up my like terms for the addition.

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$0x^6+0x^4+x^3+0x^2+2x+3$

$0x^6-x^4+0x^3-2x^2-3x+0$

$x^6+2x^4+3x^3+0x^2+0x+0$

----------------------------------------------------Adding the three products!

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8 0

4 years ago

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3 years ago

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zlopas [31]

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