Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
Answer:
Velocity = 59 feet/second
Step-by-step explanation:
h(t) = 15 + 60t – 16t2
Time t = 1 second
Let's substitute time into the equation to get the distance
h(t) = 15+60(1)-16(1)²
h(t) = 15 + 60 - 16
h(t) = 59 feet
Speed or velocity = distance/time
Distance = 59 feet
Time = 1 second
Velocity = 59/1
Velocity = 59 feet/s
Answer: I'm pretty sure I can help, just give me like 3 minutes..
-Angie
Answer:
A and D
because those are the correct ones :)
