All categories

4 years ago

Ignore the shimejis. Also if there is a calculator for this type of thing tell me please

Mathematics

1 answer:

ella [17]4 years ago

3 0

A triangle has 3 sides that equal 180, so add up the two numbers and subtract them by 180 and you have your third.83*

You might be interested in

You buy a 1:1000 scale model of the Statue of Liberty during a trip to New York City. The height of the model is 9.3 centimeters

luda_lava [24]

Scale is 1:1000
Thus 9.3cm the actual is 9.3×1000= 9300cm = 93m

8 0

3 years ago

What is the answer of 120 ×3

umka2103 [35]

Answer:

OK ANSWER IS 120×3 = 360

I HOPE IT HELPFUL

#CARRYONLEARNING

#HATEGIRL

4 0

3 years ago

Katherine uses $\frac{7}{10}$ of a gallon of red paint to paint $\frac{3}{5}$ of her wall. How many gallons of red paint will sh

scZoUnD [109]

Answer:

1.167 gallons

Step-by-step explanation:

Given that:

Fraction of red paint used = 7/10 of a gallon

Fraction of wall painted = 3/5

Gallon of paint required to paint the entire wall:

Fraction of entire wall = 1/1

7/10 paint = 3/5 wall

x paint = 1 wall

Cross multiply

(3/5)x = 7/10

Divide both sides by 3/5

3/5x ÷ 3/5 = 7/10 ÷ 3/5

(3/5)x * 5/3 = 7/10 * 5/3

x = 35 / 30

x = 7/6 = 1.167 gallons of red paint

3 0

3 years ago

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→1 3x x − 1

Reika [66]

Answer:

Step-by-step explanation:

Given the limit of a function expressed as $\lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})$ , we are to evaluate it. To evaluate it, we will simply substitute x = 1 into the function since the variable x tends to 1.

$\lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})\\\\= (\dfrac{3(1)}{1-1} - \dfrac{3}{ln1})\\\\= \dfrac{3}{0} - \dfrac{3}{0}\\\\= \infty - \infty (ind)$

Since we got an indeterminate function, we will find the LCM of the function and solve again.

$= \lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})\\\\= \lim_{x \to 1} \dfrac{3xlnx-3(x-1)}{(x-1)lnx}\\\\\\= \dfrac{3(1)ln(1)-3(1-1)}{(1-1)ln1}\\\\= \frac{3(0)-3(0)}{0(0)} \\\\= \frac{0}{0} (ind)$

Applying L'hospital rule;

$\frac{x}{y} = \lim_{x \to 1} \dfrac{d/dx(3xlnx-3(x-1))}{d/dx((x-1)lnx)}\\\\= \lim_{x \to 1} \dfrac{3x(\frac{1}{x})+ 3lnx-3)}{(x-1)\frac{1}{x} +lnx}\\\\= \lim_{x \to 1} \dfrac{3 + 3lnx-3}{(x-1)\frac{1}{x} +lnx}\\\\= \frac{3ln1}{(1-1)\frac{1}{1} +ln1}\\\\= \frac{0}{0} (ind)$

Applying L'hospital rule again;

$= \lim_{x \to 1} \dfrac{\frac{d}{dx} (3lnx)}{\frac{d}{dx} ((x-1)\frac{1}{x} +lnx)}\\\\= \lim_{x \to 1} \dfrac{\frac{3}{x} }{(x-1)\frac{-1}{x^2} + \frac{1}{x} +\frac{1}{x} }\\\\= \dfrac{\frac{3}{1} }{(1-1)\frac{-1}{1^2} + \frac{1}{1} +\frac{1}{1} }\\\\= \frac{3}{0(-1)+2}\\ \\= \frac{3}{2-0}\\ \\= 3/2$

<em>Hence the limit of the function is 3/2.</em>

7 0

4 years ago

Simplify using Quotient<br> Rule<br> 10^12 OVER 10^8

OverLord2011 [107]

Answer:

$10^4$

Step-by-step explanation:

All you have to di is subtract the exponents.

5 0

4 years ago