Answer:
tysm. Have a wonderful day...
Answer:
The work required to empty the tank is 1,580,887 J
Step-by-step explanation:
Work = mass of chocolate × acceleration due to gravity × height of chocolate
Volume of tank (cone) = 1/3πr^2h = 1/3 × 3.142 × 2^2 × 7 = 29.33 m^3
Mass of hot chocolate = density of hot chocolate × volume of cone = 1100 kg/m^3 × 29.33 m^3 = 32,263 kg
height of chocolate = 5 m
Work = 32,263×9.8×5 = 1,580,887 J
50 - [(6² - 24) + 9√25]
= 50 - [36 - 24 + 9*5]
= 50 - [12 + 45]
= 50 - 57
= -7
Answer: second option y = 2(x + 7/2)^2 + 1/2
Explanation:
1) given:
y = (x + 3)^2 + (x + 4)^2
2) expand the binomials:
y = x^2 + 6x + 9 + x^2 + 8x + 16
3) add like terms:
y = 2x^2 + 14x + 25
4) take common factor 2 of the first two terms:
y = 2 (x^2 + 7x) + 25
5) complete squares for x^2 + 7x
x^2 + 7x = [x +(7/2)x ]^2 - 49/4
6) substitue x^2 + 7x = (x + 7/2)^2 - 49/4 in the equation for y:
y = 2 [ (x + 7/2)^2 - 49/4] + 25
7) take -49/4 out of the square brackets.
y = 2 (x + 7/2)^2 - 49/2 + 25
8) add like terms:
y = 2(x + 7/2)^2 + 1/2
And that is the vertex for of the given expression.
To factor (q+3)(q+6)
q^2+6q+3q+18
q^2+9q+18
(q+9)(q+2)
