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Alecsey [184]
2 years ago
11

Interpreting composite functions in the real world The volume of air in a balloon is represented by the function v(r)=4/3 ³, whe

re r is the radius of the balloon, in
inches. The radius of the balloon increases with time, in seconds, by the function r(t) = 1/4 t².
Write a composite function that can be used to determine the volume of the balloon after t seconds. Then, select the
two true statements.

Mathematics
1 answer:
adoni [48]2 years ago
7 0

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

<h3>How to use composition between two function</h3>

Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.

If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:

V(t) = (4/3) · π · [(1/4) · t²]³

V(t) = (4/3) · π · (1/64) · t⁶

V(t) = (1/48) · π · t⁶

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

To learn on composition between functions: brainly.com/question/12007574

#SPJ1

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Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 3^3- 5(3)^2 + 6(3)

⇒ f(0) =0

Therefore , the solutions to the related equation are 0,2,3 .

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Step-by-step explanation:

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Step-by-step explanation:

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Now, in this case it is going to be

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sertanlavr [38]

Answer:

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Step-by-step explanation:

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