3 years ago

Please help!!!

Mathematics

1 answer:

Dominik [7]3 years ago

7 0

Answer:

Step-by-step explanation:

8+1=9

16+2=18

24+3=27

32+4=36

40+ 5=45

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We are given the two functions:

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Expand if desired:

$\displaystyle = x(2x^2+x-3)+2(2x^2+x-3) \\ \\ = (2x^3+x^2-3x)+(4x^2+2x-6) \\ \\\ = 2x^3 + 5x^2-x-6$

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