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3 years ago

13°38'35" to decimal degrees

2 answers:

6 0

Hi! 13°38'35'' to decimal degrees, let's go:

First, the minutes >>> (divide by 60)
1° → 60'
x ---- 38' ??

60x = 38
x = 38 / 60
x = 0.6333

After, the seconds >>> (divide by 3600)
1° → 3600''
x ---- 35'' ??

3600x = 35
x = 35 / 3600
x = 0.009722

So, now add: 13 + 0.6333 + 0.009722 = 13.64305

Result: 13.64305 decimal degrees

I hope this helps! :)

babymother [125]3 years ago

4 0

divide 35 by 3600

divide 38 by 60

add them together

35/3600 = 0.009722

38/60=0.6333

0.6333+0.009722 = 0.64305

so 13.64305 degrees. round answer as necssary

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What is the slope of the line?

Blizzard [7]

Answer:

Not enough information given

Step-by-step explanation:

To find the slope, you need two points. You put the values into this formula:

(y_2 - y_1) / (x_2 - x_1) = m

The underscores show which ordered pair, so _2 means the values from the second one.

m stands for slope.

6 0

3 years ago

Read 2 more answers

A couple plans to have children until they get a girl, but they agree they will not have more than three children, even if all

barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a girl, but they agree they will not have more than three children, even if all are boys. Assume that the probability of having a girl is 47.00%.

a) Create a probability model for the number of children they'll have.

X=1,2,3

P(X=1)=??

P(X=2)= ??

P(X=30=???

(Round to four decimal places as needed

b) Find the expected number of children.

E(X)= ???

c) Find the expected number of boys they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

= 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

= 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

= 0.148875×3 +0.46375×2+0.2491 ×1

= 1.6232

5 0

3 years ago

In a study of 250 adults, the mean heart rate was 70 beats per minute. Assume the population of heart rates is known to be appro

pantera1 [17]

The z score for a confidence level of 99% is 2.575.. You need to know this to complete this type of problem.. the other two commonly used confidence levels are 90% and 95% having z scores of 1.645 and 1.96 respectively. You need to memorize this!

To find the confidence interval, it will be defined as the sample mean plus/minus the margin of error.. Now to find the margin of error, divide the standard deviation of 12 by the square root of the number of elements in your sample(√250). Then take that result and multiply it by the Z score I mentioned above for a 99% confidence level.

In this case: the sample mean is 70 and the margin of error is approximately 1.95

So to calculate the confidence interval, do the following:
70 - 1.95 = 68.05 rounded to the nearest whole number is 68
70 + 1.95 = 71.95 rounded to the nearest whole number is 72

Looks like that would be the last choice. hope this helps.. it's been awhile since my work with statistics :-)

4 0

3 years ago

Read 2 more answers

The edges of a cube are 5 cm each and the diaganol of a face is approximately 7 cm what is the approximate area of the cross sec

xxTIMURxx [149]

Answer:

The approximate area is 35 square centimeters

Step-by-step explanation:

we know that

The cross section passing through the diagonal of opposite faces of the cube is a rectangle

the approximate area is equal to

$A=bh$

where

b is the diagonal of a face

h is the length side of the cube

we have

$b=7\ cm\\h=5\ cm$

substitute

$A=7(5)=35\ cm^2$

7 0

3 years ago

Someone can help me for all the question ?

Dvinal [7]

Answer:

1. 5

2. 3 adult tickets; 2 child tickets

3. See below

Step-by-step explanation:

2 adult tickets cost 2 × $12 = $24

Subtract $24 from $64:

$64 - $24 = $40

Divide $40 by $8:

$40 ÷ $8 = 5

Answer: 5 child tickets

x = number of adult tickets

y = number of child tickets

The total number of tickets is 5, so the first equation is:

x + y = 5

The cost of x adult tickets is 12x. The cost of y child tickets is 8y. The total cost is 12x + 8y. We are told the total cost is $52. The second equation is:

12x + 8y = 52

The system of equation is:

x + y = 5

12x + 8y = 52

Let's solve it by substitution.

Solve the first equation for x.

x = 5 - y

Now we substitute x in the second equation by 5 - y.

12(5 - y) + 8y = 52

Distribute:

60 - 12y + 8y = 52

Combine like terms on the left side:

-4y + 60 = 52

Subtract 60 from both sides:

-4y = -8

Divide both sides by 4.

y = 2

Substitute y = 2 in the first original equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

Answer: 3 adult tickets; 2 child tickets

The customer's claim is incorrect. His sum is $71. 71 is an odd number. Since all ticket prices are even numbers, it is impossible to add only even numbers and get an odd sum. A sum of several amounts of 12 and several amounts of 8 can never equal 71.

We can also show his claim is false using a system of equations.

x + y = 7

12x + 8y = 71

Use substitution.

x = 7 - y

12(7 - y) + 8y = 71

84 - 12y + 8y = 71

84 - 4y = 71

-4y = -13

y = 3.25

This means 3.25 child tickets. The problem states that tickets can be purchased only in whole numbers, so 3.25 tickets cannot be purchased, so the customer's claim is false.

4 0

2 years ago