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kvv77 [185]
3 years ago
8

Rewrite the expression g+1/6d-3/4g+1/9g-g+1/4d in standard from by combining like terms I need this ASAP AND I NEED ALL STEPS TO

RECEIVE FULL CREDIT PLEASE!
Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

(5/12)d - (23/36)g

Step-by-step explanation:

First you can eliminate g and -g to get (1/6)d - (3/4)g + (1/9)g + (1/4)d. Then you need to get common denominators to add like terms together.

1/6 = 4/24 and 1/4 = 6/24. Add them together to get (10/24)d or (5/12)d.

-3/4 = -27/36 and 1/9 = 4/36. Add them together to get (-23/36)g.

So in standard form, (5/12)d - (23/36)g

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In the 30-60-90 triangle below, side s has a length of _ and side q has a length of _.
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Step-by-step explanation:

For a 30-60-90 triangle, we know that the hypotenuse is 2x. Since we know the hypotenuse is 10, we can solve for x.

2x=10

x=5

Now that we know x is 5, we can use this to solve for s and q. The side across from 30° is just x. Since we know x, s is 5.

The side across from 60° is x√3. Since we know what x is, we can just plug in. q is 5√3.

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4 years ago
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7 0
3 years ago
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Which system is equivalent to
sammy [17]

<u>Answer:</u>

D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11

<u>Step-by-step explanation:</u>

We are given the following two expressions:

3x^2-4y^2=25

and

-6x^2-2y^2=11

Now if we look at the option D) 6x^2 - 8y^2 = 50&#10; and -6x^2 - 2y^2 = 11, we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25

and the later part -6x^2 - 2y^2 = 11 is already the same.

Therefore, the correct answer option is D)  6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

6 0
3 years ago
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