Kim sold a house for $250,000 and made a 2% commission. How much money did Kim make from commission for selling the house?

Mathematics

2 answers:

puteri [66]3 years ago

7 0

$5,000.00 because that’s the right answer thats why

Vikki [24]3 years ago

4 0

Answer:

5000

Step-by-step explanation:

2% of 250,000 is 5000

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A triangle with sides of lengths 16,30,and 35 is a right triangle? a. true b. false

Anon25 [30]

-- The square of the shortest side . . . 16² = 256
-- The square of the medium side . . . 30² = 900
-- Their sum . . . (256 + 900) = 1,156

-- The square of the longest side = 35² = 1,225

1,156 and 1,225 are not equal, so these 3 numbers
can be the sides of a triangle, but it's not a right one.

The statement is false. (choice 'b')

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Mary stated that 2.01 x 10⁶ is less than 4.8 x 10⁴ because 2.01 is less than 4.8. what was mary's mistake ?

katrin [286]

Answer:

Step-by-step explanation:

Scientific notation is always written as a number between 1 and 9.9999999 repeating. There follows a power of 10. I'm not sure which answer would help you see it clearer but

4.8 * 10^4 the decimal is shifted 4 places the right which is 48000 where you have no numbers, you use zeros.

2.01 * 10^6 means that you shift the decimal 6 places to the right.

2010000

So 2 million is larger than 48 thousand.

The other way to do it is just to look at the power. 6 is more than 4. 6 describes the number of places you move. So does 4. 6>4 so that's the larger number.

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3 years ago

Help me on number problem 5 please

AlekseyPX

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Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia

Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$