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PolarNik [594]
3 years ago
9

Brainliest,plz help

Mathematics
1 answer:
labwork [276]3 years ago
4 0

4 sqrt (32) + 6 sqrt (50)

4 sqrt (16*2) + 6 sqrt (2*25)

4 sqrt (16)*sqrt(2) + 6 sqrt (2)*sqrt(25)

4 *4*sqrt(2)+6sqrt(2)*5

16sqrt(2)+30sqrt(2)

46sqrt(2)


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seropon [69]

Answer:

a.0.0078125

b. 0.1640625

c. 0.0078125

d. 0.0078125

Step-by-step explanation:

To solve this question we can use the binomial probability function:

Prob(k\,successes\,in\,n\,trials)=\left(\begin{array}{c}n&k\end{array}\right) p^k q^{(n-k)}\\

where

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  • q is the probability that is a girl,

In this case case p=q

Then

(a) Prob(B,B,B,B,B,B,B)=1\times0.5^7

(b) Prob(5\,boys\,in\,7\,children)=\left(\begin{array}{c}7&5\end{array}\right)0.5^7

(c)Prob(G\,last\,and\,6\,boys)=Prob(B)^6Prob(G)=0.5^7

(d) Prob(G\,first\,and\,6\,boys)=Prob(G)Prob(B)^6=0.5^7

(a), (c) and (d) are equal as a result of equal probability of giving birth to a boy or a girl. (b) is different because it takes into account the different orders that births can occur

5 0
4 years ago
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3 years ago
1. 9c-3c=48A) c=9B) c=3C) c=4D) C=8
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To solve this equation, we need to subtract both, 9c - 3c:

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