Answer:
A.O(1)
Explanation:
In the implementation of queue by using linked chain the performance of the enqueue operation is O(1).We have to maintain two pointers one head and the other tailand for enqueue operation we have to insert element to the next of the tail and then make that element tail.Which takes O(1) time.
I would say the answer is b, but ⟟ might be wrong
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
Some options are add to dictionary, ignore once, ignore all, autocorrect, change, and change all.
Answer:-
(10111.001)₂
Explanation:
To convert a decimal number to a binary number we have to constantly divide the decimal number by 2 till the decimal number becomes zero and the binary number is writing the remainders in reverse order of obtaining them on each division.
Hence the binary number is 10111.001
To convert binary to hexa decimal we to make a group 4 binary bits starting from the decimal and moving outwards if the last group is not of 4 then add respective 0's and write the corresponding hexa decimal number.
<u>0001</u> <u>0111</u> . <u>0010</u>
1 7 2
Hence the hexadecimal number is 17.2
