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Aleksandr [31]
3 years ago
11

7/4 - 1.76 Please help -.-

Mathematics
2 answers:
Mariulka [41]3 years ago
4 0
7/4= 1.75
1.75-1.76= -.01
Hope this helps
Angelina_Jolie [31]3 years ago
4 0
The answer is -0.01 as a decimal
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koban [17]
5. million 6. Ten thousand
6 0
3 years ago
a line passed through the point (8,9) and has a slope of -3/4. write an equation in slope intercept form.
bagirrra123 [75]

Answer:

y = -3/4x + 3

Step-by-step explanation:

y - 9 = -3/4 (x-8)

y-9 = -3/4x -6

y = -3/4x - 6 + 9

y = -3/4x + 3

8 0
3 years ago
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
What are the values of x in the equation 4x2 + 4x - 3 = 0?
9966 [12]

Answer:

x=  0.5

or x=  -1.5

Step-by-step explanation:

Let's solve your equation step-by-step.

4x2+4x−3=0

Step 1: Factor left side of equation.

(2x−1)(2x+3)=0

Step 2: Set factors equal to 0.

2x−1=0 or 2x+3=0

x= 1/2 or x= −3/2

5 0
3 years ago
Help me solve for z, step by step if you can
zheka24 [161]

Answer:

z=6

Step-by-step explanation:

z/3 + 1/2 = 5/2

Subtract 1/2 from each side

z/3 + 1/2-1/2 = 5/2-1/2

z/3 = 4/2

z/3 =2

Multiply each side by 3

z/3*3 = 2*3

z = 6


5 0
3 years ago
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