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Harman [31]
3 years ago
7

Which statements explain the gas exchange that happens at the alveoli? Check all that apply.

Chemistry
1 answer:
kicyunya [14]3 years ago
4 0
The answer is F ! Hope this helps !
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Why do humans sweat? what is unique about water that makes sweat a useful biological process
andriy [413]
Humans sweat to expel toxins.

They also sweat because sweat helps the body cool down. During exercise, body temperature rises, sweat helps the body cool down.


Sweat also contain sodium. Which is why it’s salty.
7 0
3 years ago
Flowering plants are the most successful group of land plants. This is due, in part, to the trait that could be the label for po
jek_recluse [69]

Answer:

seeds are protected in fruits in such kind of plants.

Explanation:

The flowering plants are also known as Angiospermae, or Magnoliophyta. Flowering plants are plants that grow flowers. Such plants use seeds to reproduce, or make more plants like them.

Seeds are protected in fruits in such kinds of plants.

Examples of flowering plants are daisies, tulips, oaks, apples.

8 0
4 years ago
You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca
vova2212 [387]
The equation to be used are:

PM = ρRT
PV = nRT
where
P is pressure, M is molar mass, ρ is density, R is universal gas constant (8.314 J/mol·K), T is absolute temperature, V is volume and n is number of moles

The density of air at 23.5°C, from literature, is 1.19035 kg/m³. Its molar mass is 0.029 kg/mol.

PM = ρRT
P(0.029 kg/mol) = (1.19035 kg/m³)(8.314 J/mol·K)(23.5+273 K)
P = 101,183.9 Pa

n = 0.587 g * 1 kg/1000 g * 1 mol/0.029 kg = 0.02024 mol
(101,183.9 Pa)V = (0.02024 mol)(8.314 J/mol·K)(23.5+273 K)
Solving for V,
V = 4.931×10⁻⁴ m³
Since 1 m³ = 1000 L
V = 4.931×10⁻⁴ m³ * 1000
V = 0.493 L

7 0
3 years ago
What volume of methane gas at 237 K and 101.33 kPa do you have when the volume is decreased to 0.50 L, with a temperature of 300
Alexxandr [17]

Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.

Explanation:

Given: T_{1} = 237 K,   P_{1} = 101.33 kPa,      V_{1} = ?

T_{2} = 300 K,      P_{2} = 151.99 kPa,        V_{2} = 0.50 L

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{101.33 kPa \times V_{1}}{237 K} = \frac{151.99 kPa \times 0.50 L}{300 K}\\V_{1} = 0.592 L

Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.

8 0
3 years ago
The specific silver is How many joules of energy are needed to warm 4.37 g of silver from 25.0 degrees * C to 27.5 degrees * C ?
Alexxandr [17]

0.24J/g*degC * 4.37g * 2.5degC = 2.622J

The 2.5 degC is the difference between 25 and 27.5 deg C.

6 0
4 years ago
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