The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g
<h3>
What is the use of aluminium chloride ?</h3>
Aluminum chloride is useful for the treatment of palmar, plantar, and axillary hyperhidrosis.
Aluminum chloride has also been reported to be useful in facial and scalp hyperhidrosis
The balanced chemical equation represents the mole ratio in which the chemicals combine.
In this case, illustrates that 2 mol Al produces 2 mol Al Cl₃, hence these 2 chemicals are in a 1:1 ratio.
Thus, to produce 8.70 mol aluminium chloride, it will require 8.70 mol aluminium.
But this quantity of Al has a mass in grams of
m = n × Mr
= 8.70 mol × 27g/mol
= 234.9 g
Hence, The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g
Learn more about mole concept here ;
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B) are often quite different from each other
Think, do you think a lung cell looks and does the same as an eye cell? No, they do not.
Answer:
thoracic cavity
Explanation:
The ventral body cavity in human body is the front aspect of the human body. Ventral body cavity is combined with the combination of three components that include the thoracic cavity, the pelvic cavity and the abdominal cavity.
So, Thoracic cavity is the components of the anterior cavity that refers to the the ventral internal organs above the diaphragm.
Hence, the correct answer is "thoracic cavity".
Explanation:
It is known that density is mass of a substance divided by its volume.
Mathematically, Density = 
Therefore, calculate the mass of cyclohexane as follows.
mass of cyclohexane = Density × volume
= 
= 15.58 g
or, = 0.01558 kg (as 1 kg = 1000 g)
As, K_{f} of cyclohexane = 
molality = 
= 0.26 m
Also, molality is the number of moles of solute present in kg of solvent.
Mathematically, molality = 
0.26 = 
No. of moles = 
As, No. of moles = 
molar mass = 87.0 g/mol
Thus, we can conclude that molar mass of unknown substance is 87.0 g/mole.
