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3 years ago

9

Find greatest 3 digit number divisible by 8,10,12

1 answer:

schepotkina [342]3 years ago

5 0

The greatest 3 digit number divisible by the 8, the 10, and the 12 is 960. The simplest way of finding the number is to multiply all the divisible factor which is the 8, the 10, and the 12 that results in 960 (8*10*12). If this multiply operation results in more than 3 digit number, therefore we must analyze the factor of the result and eliminate it.

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vivado [14]

Answer: 16x + 16

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the area of the colored figure in a letter phenomenon is

(2x + 4)² - (2x)² = 4x² + 16x + 16 - 4x² = 16x + 16

Step-by-step explanation:

3 0

3 years ago

5. Find the coordinates of the midpoint of the segment whose endpoints are 1l(6, 4) and K(2. 8).

Cerrena [4.2K]

Answer:

5. D (4,6)

6. B (7.8)

Step-by-step explanation:

5. Add the two X coordinates (6+2) and divide that by 2 (8/2=4), do the same for the two Y coordinates (4+8=12, 12/2=6)

6. Use the distance formula $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}\\$

Input the coordinates $\sqrt{(3-8)^{2}+(8-2)^{2}$

3 0

3 years ago

Read 2 more answers

I need help with #14 & #15 quickly!

arsen [322]

Answer:

#14 $\frac{3m^{12} n^{10}-m^{8} n^{10}}4\\$ #15 $-448y^{32}x^{5}$

Step-by-step explanation with pictures.

I hope this helps! :D

4 0

3 years ago

What are the vertical asymptotes of f(x) = 10/ x^2 - 1

Veronika [31]

Vertical asymptotes ares found where the function is undefined. f(x) is undefined when the denominator equals zero:

x^2-1=0

<em>*Add 1 to both sides*</em>

x^2=1

<em>*Take the square root of both sides*</em>

x=+/-1

There are vertical asymptotes at x=-1 and x=1.

Hope this helps!!

8 0

4 years ago

F(x) = 3 sin x<br> can you graph

kirill [66]

Answer:

Look at the photo

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3 years ago