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3 years ago

I need help with #14 & #15 quickly!

Mathematics

1 answer:

arsen [322]3 years ago

4 0

Answer:

#14 $\frac{3m^{12} n^{10}-m^{8} n^{10}}4\\$ #15 $-448y^{32}x^{5}$

Step-by-step explanation with pictures.

I hope this helps! :D

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A real estate agent earned $7200 commission on a property sale of $240,000. What is her rate of commission?

cluponka [151]

The real estate agent has a commission rate of 33.3%

if youy divide 240000 by 7200 then you would get 33.33333333

which would mean she has a (1/3) commission rate. hope this helps you out!

8 0

4 years ago

Me.Hatch bought 4 round-trip airplan tickets for $417 each. He also paid $50 in baggage fees. How much did Mr.Hatch spend

Stella [2.4K]

4 * 417 + 50

1668+50

1718

Mr Hatch spent $1718

5 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP ME!

Sladkaya [172]

Answer:

y=3/4m

Step-by-step explanation:

All proportional relationships have the form y=mx where m is the rate of change from the families donations x to the business donations y. We can find the rate of change m by substituting values we already know. We know when x=$12 then y=$9.

9=m*12

We solve for m by dividing by 12 on both sides.

m=9/12

This simplifies to 3/4 so

m=9/12=3/4.

The equation is y=3/4m

3 0

3 years ago

Write two numbers so that

lana [24]

-5 and 2 would work.

5 0

3 years ago

Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7

Nutka1998 [239]

As a Bernoulli equation:

$x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6$

Let $z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}$ . The ODE becomes

$-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4$
$\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4$
$x^6z=-6\displaystyle\int x^4\,\mathrm dx$
$x^6z=-\dfrac65x^5+C$
$z=-\dfrac6{5x}+\dfrac C{x^6}$
$y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}$
$y=\dfrac1{\frac C{x^6}-\frac6{5x}}$
$y=\dfrac{5x^6}{C-6x^5}$

With $y(3)=6$ , we get

$6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2$

so the solution is

$y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}$

which is valid as long as the denominator is not zero, which is the case for all $x\neq\sqrt[5]{\dfrac{4131}{12}}$ .

8 0

3 years ago