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11Alexandr11 [23.1K]
4 years ago
11

What are the vertical asymptotes of f(x) = 10/ x^2 - 1

Mathematics
1 answer:
Veronika [31]4 years ago
8 0

Vertical asymptotes ares found where the function is undefined.  f(x) is undefined when the denominator equals zero:

x^2-1=0

<em>*Add 1 to both sides*</em>

x^2=1

<em>*Take the square root of both sides*</em>

x=+/-1

There are vertical asymptotes at x=-1 and x=1.

Hope this helps!!

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Answer:

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Step-by-step explanation:

Let's say x represents Joes's account.

And y represents Chandra.

Since Joses account was 1 more than one half of chandra, the amount for Joes would be x = 1/2*y + 1

Now we can just say y = Chandra's amount.

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4 0
3 years ago
A lateral thoracic spine on a 33-cm patient is usually taken using 100 mA (large focal spot), 0.5 seconds, 86 kVp, 40-inch SID,
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A 0.13 sec and a 86 kVp technical changes are the changes that would have to produce the radiographic density and the contrast that are more similar to the original.

<h3>What is the radiographic density?</h3>

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It is known that based on the values that we have here the density and contrast would have to be of the given kvp of 86 and 0.13 seconds in order to be said to be similar to the original.

Read more on the radiographic density here:

brainly.com/question/14332593

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Step-by-step explanation:

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