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denis-greek [22]
3 years ago
7

The length of a reticular garden is represented by 3x-4 and the width is represented by 2x-5 which of the following represents t

he total area of the garden?
Mathematics
1 answer:
agasfer [191]3 years ago
7 0
Area = length*width
         = (3x-4)(2x-5)
         = 6x^2 - 15x - 8x + 20
         = 6x^2 - 23x + 20
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kirza4 [7]

Answer:

7% discount

Step-by-step explanation:

The discounted amount is $2.31 incase you needed that too

8 0
3 years ago
What is -5/9+(-4/3)- 2/3
inessss [21]

Answer:

-23/9 or -2 5/9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help!
arsen [322]

The instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.

<h3>What is the instantaneous rate of change of the function at the given point?</h3>

The instantaneous rate of change is simply the change in the derivative value at a specific point.

Given the data in the question;

  • f(x) = −4x² − 3x + 1
  • Point x = -3

To determine the instantaneous rate of change of the function, first find the derivative of the function.

f(x) = −4x² − 3x + 1

Applying sum rule, with respect to x

d/dx[ -4x² ] + d/dx[ -3x ] + d/dx[ 1 ]

[ 2 × -4x¹ ] + [ 1 × -3x⁰ ] + d/dx[ 1 ]

[ -8x ] + [ -3 ] + d/dx[ 1 ]

-8x - 3 + d/dx[ 1 ]

Differentiate using constant rule

-8x - 3 + [ 0 ]

-8x - 3

f'(x) = -8x - 3

Next, plug x = -3 into the derivative and simplify.

f'(x) = -8x - 3

f'(-3) = -8(-3) - 3

f'(-3) = 24 - 3

f'(-3) = 21

Therefore, the instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.

Learn more about instantaneous rate of change here: brainly.com/question/28122560

#SPJ1

7 0
1 year ago
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
3 years ago
If x is a whole number and 437 = (21 + x)(21 - x), then x =
IrinaK [193]
<span>437 = (21 + x)(21 - x), then x = 2, -2</span>
3 0
4 years ago
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