Answer:
8/21
I don't think that it can be simplified further....
Answer:
0.5
Step-by-step explanation:
Solution:-
- The sample mean before treatment, μ1 = 46
- The sample mean after treatment, μ2 = 48
- The sample standard deviation σ = √16 = 4
- For the independent samples T-test, Cohen's d is determined by calculating the mean difference between your two groups, and then dividing the result by the pooled standard deviation.
Cohen's d =
- Where, the pooled standard deviation (sd_pooled) is calculated using the formula:
- Assuming that population standard deviation and sample standard deviation are same:
SD_1 = SD_2 = σ = 4
- Then,
- The cohen's d can now be evaliated:
Cohen's d =
Answer:
Let x be odd such that LCM {x,40} = 1400 .
Since 1400 = 23×52×7 , then
x ∈ {5m×7n∣(m,n) ∈ {0,1,2}×{0,1}} .
By testing these values, we find that x = 175 .
Answer:
(6,-7)
Step-by-step explanation:
take b as x2,y2
then apply mid point formula
x=(x1+x2)/2
y=(y1+y2)/2
Answer: 120 ways
Step-by-step explanation: In this problem, we're asked how many ways can 5 people be arranged in a line.
Let's start by drawing 5 blanks to represent the 5 different positions in the line.
Now, we know that 5 different people can fill the spot in the first position. However, once the first position is filled, only 4 people can fill the second spot and once the second spot is filled, only 3 people can fill the third spot and so on. So we have <u>5</u> <u>4</u> <u>3</u> <u>2</u> <u>1</u>.
Now, based on the counting principle, there are 5 x 4 x 3 x 2 x 1 ways for all 5 spots to be filled.
5 x 4 is 20, 20 x 3 is 60, 60 x 2 is 120, and 120 x 1 is 120.
So there are 120 ways for all 5 spots to be filled which means that there are 120 ways that 5 people can be arranged in a line.
I have also shown my work on the whiteboard in the image attached.