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2 years ago

Simplify each product. Write in standard form. (EXPLAIN)

1 answer:

5 0

Simplify. Write each answer in standard form. 54412 + 2x + 5) + (7x2 - 5x + 2). 6-(9612 — 4 - 5a) — (12a — 6612 + 3). 7. —4m2 + m ... Open-Ended Write a trinomial with a degree of 6. 10. Write the ... (3x + 5)(7x2 - 2x + 1) ... Write your answer in simplest form. Factor each expression. 31. W2 » 5w — 14. 33.

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PLEASE HELP ME ITS TIMED!!

Sindrei [870]

Answer:

x=40°

Step-by-step explanation:

(x-5)+(x+15)=90°

2x+10=90

2x=80

x=40°

6 0

2 years ago

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Subtract : 13.257 from 25.8 Pls Someone Help

Roman55 [17]

Answer:

12.543

Step-by-step explanation:

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2 years ago

F(x) = 3x - 1 and g(x) = x2 -x find (f/g(8) answer choices a)-23/6 b)4 c)-4 d)23/6

Lilit [14]

Answer:

all answer wrong with you

Step-by-step explanation:

f(x)=3x-1

f(8)=3.8-1

=24-1

=23

f(g)=x2-x

f(8)=8.2-2

=16-2

=14

7 0

3 years ago

The initial number of carbon-14 atoms in the organism

jenyasd209 [6]

Answer: The death is 500, there will be 125 carbon-14 atoms, and after 25,000 years.

Step-by-step explanation:

I just took a test and got it right, I can't do math (;

4 0

2 years ago

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This is a 2 part question. Need help with both questions please! Use the triangle for both parts of the question. Click on the f

ollegr [7]

Answer:

Part A) Option A. QR= 3 cm

Part B) Option B. SV=6.5 cm

Step-by-step explanation:

step 1

Find the length of segment QR

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem Triangle QRW and Triangle QSV are similar by AA Similarity Theorem

$\frac{QR}{QS}=\frac{QW}{QV}$

we have

$QS=9\ cm$ ---> because S is the midpoint QT (QS=TS)

$QW=2\ cm$ --->because V is the midpoint QU (QW+WV=VU)

$QV=6\ cm$ --->because V is the midpoint QU (QV=VU)

substitute the given values

$\frac{QR}{9}=\frac{2}{6}$

solve for QR

$QR=9(2)/6=3\ cm$

step 2

Find the length side SV

we know that

The Mid-segment Theorem states that the mid-segment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this mid-segment is half the length of the third side

In this problem

S is the mid-point side QT and V is the mid-point side QU

therefore

SV is parallel to TU

and

$SV=(1/2)TU$

$SV=(1/2)13=6.5\ cm$

3 0

3 years ago

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