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3 years ago

Simplify each product. Write in standard form. (EXPLAIN)

1 answer:

5 0

Simplify. Write each answer in standard form. 54412 + 2x + 5) + (7x2 - 5x + 2). 6-(9612 — 4 - 5a) — (12a — 6612 + 3). 7. —4m2 + m ... Open-Ended Write a trinomial with a degree of 6. 10. Write the ... (3x + 5)(7x2 - 2x + 1) ... Write your answer in simplest form. Factor each expression. 31. W2 » 5w — 14. 33.

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What is the length of side AB of parallelogram ABCD? units 4g - 8 B q+4

Andrews [41]

Answer:

8 units

Step-by-step explanation:

» Concepts

Parallelogram Side Theorem states that the opposite sides of a parallelogram are congruent, meaning they have the same length.

» Application

In this case, we're asked to apply the theorem to find the value of q and then find the length of AB. Thus, we have to set up the equation 4q - 8 = q + 4.

» Solving

Step 1: Subtract q from both sides.

$4q-8-q=q+4-q$
$3q-8=4$

Step 2: Add 8 to both sides.

$3q-8+8=4+8$
$3q=12$

Step 3: Divide both sides by 3.

$3q/3 = 12/3$
$q=4$

Step 4: Plug in the value of q for side AB.

$4(4)-8$
$16-8$
$8$

Therefore, the answer is 8 units.

6 0

2 years ago

Can someone help please!!!!

Nuetrik [128]

Step-by-step explanation:

pretty sure it's 66 because the two lengths added together is 66

7 0

4 years ago

Make x the subject 5y + 2x = 25

Tpy6a [65]

Answer:

x = -5/2 y +25/2

Step-by-step explanation:

5y + 2x = 25

Subtract 5y from each side

5y + 2x -5y= -5y+25

2x = -5y +25

Divide by 2

2x/2 = -5y/2 +25/2

x = -5/2 y +25/2

3 0

3 years ago

A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o

vivado [14]

Since $\rho=\dfrac mV$ (density = mass/volume), we can get the mass/weight of the liquid by integrating the density $\rho(x,y,z)$ over the interior of the tank. This is done with the integral

$\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx$

which is more readily computed in cylindrical coordinates as

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}$

7 0

3 years ago

Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =

Elza [17]

Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
$\sin B=\frac{opposite}{hypotenuse} = \frac{3}{5}$ and
$\cos B = \frac{adjacent}{hypotenuse} = \frac{4}{5}$ .

Since O lies in second quadrant $\cos O\ \textless \ 0$ and
$\cos O= -\cos B =- \frac{4}{5}$ .
Answer: $\cos O=- \frac{4}{5}$ .

3 0

4 years ago