To transform the left side of the equation into the right side under the interval (0 < θ < π/2), the missing trigonometric identity to complete the equation is cos2 θ = 1- sin2 θ. This is a trigonometric identity specifically under the <span>Pythagorean Identities</span>
We know that
The triangle inequality<span> states that for any </span>triangle, t<span>he sum of the lengths of any two sides of a </span>triangle<span> is greater than the length of the third side
</span>so
case <span>A. 81 mm, 7 mm, 6 mm
6+7 is not > 81
case </span><span>B. 81 mm, 7 mm, 72 mm
72+7 is not > 81
case </span><span>C. 81 mm, 7 mm, 88 mm
81+7 is not > 88
case </span><span>D. 81 mm, 7 mm, 77 mm
81+7 is > 77------> ok
77+7 is > 81-----> ok
81+77 is > 7-----> is ok
the answer is the option
</span>D. 81 mm, 7 mm, 77 mm
Answer:
270a^2b^2
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
i^1 = i
i^2 = - 1
i^3 = i^2 * i = - 1
i^4 = i^2 * i^2 = -1 * -1 = 1
Now the circle just repeats itself. So what you do is find out the remainder of i^97 which you divide by 4. What you get is 24 with a remainder of 1.
So i^97 = i
i - i = 0
The answer is 0
I think it’s 54% bc it’s close to 50, but 27-23=4
