Graph the equation. y = 2 sqrt. x

Mathematics

1 answer:

777dan777 [17]3 years ago

3 0

A graphing calculator or spreadsheet program can do this for you. Below is a plot from the Desmos on-line graphing calculator.

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F(x) = x3 + 6x2 – x f(x) = 30?

xxMikexx [17]

Answer and Step-by-step explanation:

The answer is 2 (which is equal to x).

If you were to plug 2 in to the function, the result if 30.

$x^{3}+ 6x^{2} -x\\\\\\\\(2)^3+6(2)^2 - 2 = 30 = f(2)$

#teamtrees #PAW (Plant And Water)

7 0

2 years ago

You know that

spayn [35]

So remember that percent means parts out of 100 so
52%=52/100=0.52

26%=26/100=0.26
'of' means multily

0.52 times x=65
divide both sides by 00.52
x=125

26% of a number is 39
0.26 times y=39
divide both sides by 0.26
y=150

x=125
y=150
y is greater

you know that becuase we know that 52% is exatly twice of 26% so therefor, if x=y then 52% of x is half of 26% of y so to compare them, we just divide the 65 number by 2 to find 26% of that number to get 65/2=32.5
32.5<39 so x is smaller number

7 0

3 years ago

John and Tim are looking at the equation the square root of the quantity of 3 times x minus 4 equals square root of x . John say

IgorC [24]

The equation is
3x - 4 = sqrt(x)
where 'sqrt' is shorthand for 'square root'

Let's solve the equation. To do so, we square both sides. Then we get everything to one side
3x - 4 = sqrt(x)
(3x - 4)^2 = (sqrt(x))^2
9x^2 - 24x + 16 = x
9x^2 - 24x + 16-x = x-x
9x^2 - 25x + 16 = 0

Now use the quadratic formula. See the attached image for those steps.

After using the quadratic formula the two possible solutions are x = 1 or x = 16/9

We need to check each possible solution to see if it is extraneous or not.

----------------------------

Checking x = 1

3x - 4 = sqrt(x)
3*1 - 4 = sqrt(1)
3 - 4 = 1
-1 = 1

The final equation is false, so x = 1 is not a true solution

x = 1 is extraneous.

So far, John is correct; however, we need to see the nature of the possible solution x = 16/9

So let's check it
----------------------------

Checking x = 16/9

3x - 4 = sqrt(x)
3*(16/9) - 4 = sqrt(16/9)
48/9 - 4 = 4/3
16/3 - 4 = 4/3
16/3 - 12/3 = 4/3
(16 - 12)/3 = 4/3
4/3 = 4/3

The last equation is true, so x = 16/9 is a proper solution.

This solution is considered non-extraneous. So Tim is also correct
----------------------------

They are both correct because there are two possible solutions. One of which is extraneous (x = 1) and the other is non-extraneous (the fraction x = 16/9)