Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Answer:
Infinite solutions.
Step-by-step explanation:
Let's solve your system by substitution.
3y=9x+15;3x−y=−5
Rewrite equations:
3x−y=−5;3y=9x+15
Step: Solve 3x−y=−5 for y:
3x−y=−5
3x−y+−3x=−5+−3x(Add -3x to both sides)
−y=−3x−5
−y −1 −1=−3x−5
(Divide both sides by -1)
y=3x+5
Step: Substitute 3x+5 for y in 3y=9x+15:
3y=9x+15
3(3x+5)=9x+15
9x+15=9x+15(Simplify both sides of the equation)
9x+15+−9x=9x+15+−9x(Add -9x to both sides)
15=15
15+−15=15+−15(Add -15 to both sides)
0=0
Hello lucker
11x - 9x = 2x
-2 + 15 = 13
so...
2x + 13
The answer is D
<span>2^3x3x5^2
= 8 x 3 x 25
= 600</span>
X ≥ -3
y ≥ 5x - 9
3x + y ≤ 15
3(-3) + (5x - 9) ≤ 15
-9 + (5x - 9) ≤ 15
(-9 - 9) + 5x ≤ 15
-18 + 5x ≤ 15
<u>+ 18 + 18</u>
<u>5x</u> ≤ <u>33</u>
5 5
x ≤ 6.6
y ≤ 5(6.6) - 9
y ≤ 33 - 9
y ≤ 24
(x, y) ≤ (6.6, 24)