Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So
Given that 
normal sampling distribution can not be used
Answer:
The wrt=itten expressions are too difficult to interpret properly. I did my best but I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>
Step-by-step explanation:
"Negative 3 x minus one-half 4 y"
-3x- (1/2)4y
<u>or -3x - 2y</u>
<u>=====</u>
The answer options are too garbled for me to make sense of them. Are they:
1. 2 y minus 5 x minus one-half 2 y : 2y -5x - (1/2)2y; <u>y -5x</u> ?
2. 2 x Negative 2 x minus one-half 6 y : 2(-2x)- (1/2)6y; <u>-4x - 3y</u> ?
3. 3 x Negative 3 x minus three-fourths 4 y : 3x(-3x) - (3/4)4y; <u>-9x -3y</u> ?
4. one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:
(1/4)(-3y) - (3/4)7y - (1/4)(-3x); -(3/4)y -(21/4)y + (3/4)x; -(24/4)y + (3/4)x; ?
I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>
Answer:
8n - 3.9
Step-by-step explanation:
Given
- (- 8n + 3.9 ) ← multiply each term in the parenthesis by - 1
= 8n - 3.9
It cannot be simplified...
