Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan.
Reduce the fraction to lowest terms.
Click once to select an item at the bottom of the problem. Click again to drop the item in its correct place.
Reduce the fraction to lowest terms.
Click once to select an item at the bottom of the problem. Click again to drop the item in its correct place.
1 answer:
Consider the fraction .
1. You can see that the denominator 4k+28 can be simplified to expression 4(k+7), because 4k=4·k and 28=4·7, so using the distributive property you can write that 4k+28=4(k+7).
2. Then the initial fraction becomes .
3. The nominator and the denominator have the common divisor k+7, then you can divide top and bottom by k+7:.
Answer:
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Answer:
Option (4)
Step-by-step explanation:
From the graph attached,
A, B and C are the points based at the heights and valleys of the given curve.
y-coordinates of these points always decide, whether the point is a local maxima or local minima.
y-coordinate of A → -4
y-coordinate of B → 0
y-coordinate of C → -4
Ends of the curve are moving towards infinity, so the absolute maximum is not defined.
Local minimum → -4
Local maximum → 0
Therefore, point representing local maximum is B(0, 0).
Points representing local minimum are A(-2, -4) and C(2, -4).
Option (4) will be the correct option.
