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VLD [36.1K]
3 years ago
8

a 136 foot tall cell phone tower casts a 79.9 foot shadow. find the shadow length for a nearby 40 foot telephone pole

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0

Given :

A 136 foot tall cell phone tower casts a 79.9 foot shadow.

To Find :

The shadow length for a nearby 40 foot telephone pole .

Solution :

We know , the ratio of height and shadow , will be same for every object .

Let , length of shadow of pole is x .

So ,

\dfrac{79.9}{136}=\dfrac{x}{40}\\\\x=\dfrac{79.9\times 40}{136}\ foot\\\\x=23.5\ foot

Therefore , the length of shadow of tower is 23.5 foot .

Hence , this is the required solution .

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What is the side length of a 36 inch cube
Vladimir [108]

The side length is 3 inches

<h3>What is the perimeter of a cube?</h3>

The formula for perimeter of a cube is given as:

Perimeter = 12 × side length

We have that;

  • Perimeter = 36 inches
  • Side length be x

Substitute into the formula

12x = 36

Divide both sides by 12

12x/12 = 36 / 12

x = 3 inches

The side length is x and equal to 3 inches.

Hence, the side length is 3 inches

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brainly.com/question/1972490

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8 0
2 years ago
Please help i need help please
posledela

Answer:

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Step-by-step explanation:

7 0
3 years ago
I need help with #39-42, please explain.
shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


3 0
3 years ago
What is the solution of the system? ​
Lubov Fominskaja [6]

Answer:

The answer is B

Step-by-step explanation:

x is equal to the +3

where Y is equal to the +3

7 0
3 years ago
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Please help and show clear instructions will give brainliest !
Tems11 [23]

Answer:

Answer is 3 because

Step-by-step explanation:

a=2

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so 39/13 = 3

3 0
3 years ago
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