The sample space for the two identical dice (outcomes):
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
<span>(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)</span>
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<span>So if Elizabeth rolls each cube once, there is 36 (6 x 6) possible outcomes.</span>
<span>Let E = event of getting a sum of 10.</span>
<span>The number which is a sum 10 will be:</span>
E = [(4,6), (5,5),(6,4)]
P(E) = number of favorable outcomes divided by total number of possible outcomes
= 3 / 36 or 0.083
