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Leto [7]
3 years ago
12

X=7w^+4w-6 and y=w^-11w+13

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0
Although the terms might seem intimidating, this is a simple substitution problem.

X + Y = _______
Substitute the values of X and Y in terms of w
(7w^2 + 4w - 6) + (w^2 - 11w + 13) = ______
Now all you need to do is combine like terms (terms that have the same variables raised to the same power)
8w^2 - 7w + 7

Final Answer: 8w^2 - 7w + 7
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The area of a rectangle is 42 ft squared, and the length of the rectangle is 5 ft more than twice the width. Find the dimensions
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Answer:

<h3>Length = 12 ft</h3>

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Step-by-step explanation:

Given,

Area of rectangle = 42 \:  {ft}^{2}

Width = X

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Now,

x(2x + 5) = 42

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2x(x + 6) - 7(x + 6) = 0

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Either

2x - 7 = 0

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Or,

x + 6 = 0

x = 0 - 6

x =  - 6

Negative value can't be taken.

So, width = \frac{7}{2} ft

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