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Goshia [24]
3 years ago
5

Item 9 A surveyor is standing 118 feet from the base of the Washington Monument. The surveyor measures the angle of elevation fr

om the ground to the top of the monument to be 78∘. Find the height h of the Washington Monument to the nearest foot. Item 9 A surveyor is standing 118 feet from the base of the Washington Monument. The surveyor measures the angle of elevation from the ground to the top of the monument to be 78∘. Find the height h of the Washington Monument to the nearest foot.

Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

555 ft

Step-by-step explanation:

aee the attached figure to better understand the problem

we know that

In the right triangle ABC

tan(78^o)=\frac{AB}{BC} ----> by TOA (oppsoite side divided by the adjacent side)

substitute the given values

tan(78^o)=\frac{h}{118}

solve for h

h=tan(78^o)(118)=555\ ft

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Answer:

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11. x^2-15x+3

Step-by-step explanation:

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3 years ago
Sara was thinking of a number. Sara halves the number and gets an answer of 38.5. Form an equation with x for the information
lbvjy [14]

Answer:The equation wth x in the information can be written as

1/2 x = 38.5 , Upon solving, the number = 77

Step-by-step explanation:

Let the number Sara was thinking about be x

halving the number to get an answer = 38.5 can be expressed as

 1/2 X = 38.5

The equation with x in the information can be written as

1/2 x = 38.5

solving it becomes

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4 0
3 years ago
In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat
Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

427 had paid for coaching courses and the remaining 2733 had not.

This means that n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0
3 years ago
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