Start at 100.Create a pattern that subtracts 9 from each number.Stop when u have 5 numbers

Mathematics

1 answer:

attashe74 [19]2 years ago

5 0

Answer:

equation: x-9=y

x=ur number

y=ur answer

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Algebra help please 100% correct only

shutvik [7]

2x + 3y + 2(x - y) - 3x

First you apply the distributive property:

2x +3y + 2(x) - 2(y) - 3x
2x + 3y +2x - 2y - 3x

The you combine like terms:

2x + 2x - 3x +3y - 2y
4x - 3x + y
x (x could also be 1x) + y (y could also be 1y)

The answer is x + y or 1x + 1y

5 0

3 years ago

Read 2 more answers

Please help?

Mazyrski [523]

Answer:

$23\sqrt{3}\ un^2$

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

$A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\$

2. Note that

$A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2$