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brilliants [131]
3 years ago
11

Help please with dis

Mathematics
1 answer:
love history [14]3 years ago
8 0
I think x = 5, because you need to find the ratio between the two triangles.
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A group of students takes a test and the average score is 72. One more student takes the test and receives a score of 88 increas
Stells [14]

Answer:

3 student.

Step-by-step explanation:

From the first statement:

Let the total score be T

Let the total number of student be x

The average of the score = 72

Average = Tota score / number of student

72 = T/x

Cross multiply

T = 72x ..... (1)

Second statement:

One more student took the test and the average becomes 76 with the student having a score of 88.

Therefore,

Overall score = T + 88

Total student = x + 1

Average = 76

Average = overall score / total number of student

76 = (T + 88) /(x + 1)

Cross multiply

76(x + 1) = T + 88

Clear bracket

76x + 76 = T + 88

From equation 1

T = 72x

76x + 76 = 72x + 88

Collect like terms

76x – 72x = 88 – 76

4x = 12

Divide both side by the coefficient of x i.e 4

x = 12/4

x = 3

Therefore, the initial number of the student were 3.

4 0
3 years ago
WILL GIVE BRAINLIEST TO PERSON WHO ANSWERS
Tpy6a [65]
A² - 225 = (a-15)(a+15)
..................................................................
7 0
3 years ago
How to solve and what is the answer
TiliK225 [7]
Two ways: 
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1


x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)]  if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6]  but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/-  [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]

7 0
3 years ago
- What is 90% of 250?
steposvetlana [31]

The answer to your question is 225

8 0
3 years ago
Prove that C(50,3) + C(50,4) = C(51,4)
valkas [14]

By definition of the binomial coefficient,

C(n,k) = \dfrac{n!}{k!(n-k)!}

so we have

C(50,3) + C(50,4) = \dfrac{50!}{3!47!} + \dfrac{50!}{4!46!} \\\\ = \dfrac{50!}{3!46!} \left(\dfrac1{47} + \dfrac14\right) \\\\ = \dfrac{50!}{3!46!} \times \dfrac{51}{188} \\\\ = \dfrac{51!}{3!46!} \times \dfrac1{4\times47} \\\\ = \dfrac{51!}{4!47!} \\\\ = \dfrac{51!}{4!(51-4)!} = C(51,4)

as required.

5 0
2 years ago
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