$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{9}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-7}{4-(-2)}\implies \cfrac{9-7}{4+2}\implies \cfrac{2}{6}\implies \cfrac{1}{3}$

7 0

4 years ago

Read 2 more answers

You are graphing y < 2x + 1. What type of line do you use and where do you shade?

bazaltina [42]

Since there isn't a line under the < sign, this means that we used a dotted or dashed line. The dotted or dashed line indicates that we do NOT include the boundary as part of the solution set.

Since y is isolated and we have a less than sign, this means we shade below the dashed/dotted boundary line. Specifically, the boundary line is the graph of y = 2x+1. This boundary line goes through (0,1) and (1,3). Again, points on this boundary line are NOT part of the solution set.

So in summary we have:
A dashed or dotted boundary line
The shaded region is below the dashed/dotted boundary line.

3 0

4 years ago

Select all expressions that are equivalent to 2( - 2x + 5) +x

Firdavs [7]

Answer:

2) -3x+10

4) -4x+10+x

Step-by-step explanation:

Use the distributive property to get rid of the parentheses.

(2 × -2x) + (2 × 5) + x

-4x + 10 +x is correct, but the x's can be combined.

(-4x + x) + 10 = -3x + 10

3 0

3 years ago