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kotykmax [81]
3 years ago
15

Simplify the radical expression. EXPLAIN ALL YOUR STEPS. sqrroot 363-3sqrroot 27

Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

2√3

Step-by-step explanation:

\tt\sqrt{363}-3\sqrt{27}= \sqrt{11^2\cdot3}-3\sqrt{3^2\cdot3}= 11\sqrt{3}-9\sqrt{3}=2\sqrt{3}

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Simplify the radical expression.
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To simplify this fraction, multiply the entire fraction by the conjugate of the denominator. The conjugate of a square root and a number being added to it would be the number <em>subtracted </em>from the square root. In other words, the conjugate of \sqrt{a} + b would be\sqrt{a} - b.


Applying that information to our fraction shown here, the conjugate of the denominator would be \sqrt{3} - 4. We will multiply both the numerator and denominator of our original fraction by this expression to obtain our answer, as shown below.


\Big(\dfrac{1}{\sqrt{3} + 4}\Big)\Big(\dfrac{\sqrt{3} - 4}{\sqrt{3} - 4}\Big)

\dfrac{\sqrt{3} - 4}{3 - 16}

\dfrac{4 - \sqrt{3}}{13}


Our answer is \boxed{\dfrac{4 - \sqrt{3}}{13}}.


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