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Phoenix [80]
4 years ago
10

The solar energy received at each area of earth is not the same this is the driving force for the earth ___

Chemistry
2 answers:
Sonbull [250]4 years ago
5 0

the answer is : winds


Orlov [11]4 years ago
3 0
I think its tilt but I'm not sure
You might be interested in
9) Which of the following types of cells do not have membrane bound
Brut [27]

Answer:

i don't know

Explanation:

I really don't get dis and i need help thanks peeps

3 0
3 years ago
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L
Yanka [14]

Answer:

Kp = 7.4727

Explanation:

Let's write the balanced equilibrium reaction:

2NH₃ <-------> N₂ + 3H₂     Kp = ??

Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:

         2NH₃ <-------> N₂ + 3H₂  

I.         4,5                 0        0

C.       -2x                +x     +3x

E.        4,5-2x            x       3x

According to this chart, the Kp expression should be:

Kp = (PH₂)³ * (PN₂) / (PNH₃)²   (1)

The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:

Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²

Kp = 39.5307 / 5.29

<h2>Kp = 7.4727</h2>

Hope this helps

5 0
3 years ago
When pentyne is reacted with hydrogen gas what products is formed​
Tpy6a [65]

c5h10

c5h12     ds dsvvdsldnvfsndvjsbdjfs             df

6 0
3 years ago
If the reaction 2HgO --&gt; 2Hg + O2 is endothermic, which bonds are the strongest?
Alika [10]
  • Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
  • If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic

Now

  • HgO is Omitted from our solution option.

Hg is a atom so no bonds hence no bond strength occurs.

  • O_2 is a molecule and so it's our answer .
3 0
2 years ago
Check all that apply.
White raven [17]

Answer:

4 for C in CH4

+4 for C in CO2

-2 for O in all substances

+1 for H in both CH4 and H2O

option 1,2,3 and 4 are correct. Option 5 is not correct

Explanation:

Step 1: Data given

Oxidation number of H = +1

Oxidation number of O = -2

Step 2: The balanced equation

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: The oxidation numbers

-4 for C in CH4

 ⇒ Oxidation number of H = +1

    ⇒ 4x +1 = +4

C has an oxidation number of -4

This is correct.

+4 for C in CO2

 ⇒ Oxidation number of O = -2

    ⇒ 2x -2 = -4

C has an oxidation number of +4

This is correct.

-2 for O in all substances

⇒ this is correct, the oxidation number of O is always -2 (except in H2O2 and Na2O2)

This is correct.

+1 for H in both CH4 and H2O

⇒ this is correct, the oxidation number of H is always +1 (except in metal hydrides).

This is correct.

+4 for O in H2O

 ⇒ Oxidation number of H = +1

    ⇒ 2x +1 = +2

The oxidation number of O is -2

This is not correct

5 0
3 years ago
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