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Alex777 [14]
3 years ago
5

which of these is the term that refers to a specific group of consumers toward which a company aims its products and services br

ainly
Chemistry
1 answer:
Sindrei [870]3 years ago
3 0
Target market.

That's my guess.  You didn't list any options.
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A 17.3 g sample of Caso, is found to contain 5.09 g of Ca and 8.13 g of O. Find the mass of sulfur in a sample of CaSo, with a
hammer [34]

Answer:

4.08g

Explanation:

17.3=(5.09+8.13+S)

4 0
3 years ago
4.How many atoms of silver are in 100 grams of silver?
zvonat [6]

Answer:

5.58x1023Agatoms 5.58 x 10 23 A g a t o m s

Explanation:

After determining the moles of the sample, we can convert it to the number of atoms using the Avogadro's number.

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3 years ago
How many formula units are 113.5 grams of Ca(OH)2
Sav [38]

Answer:

Molecular Formula Ca(OH)2 or CaH2O2

Synonyms CALCIUM HYDROXIDE 1305-62-0 Slaked lime Hydrated lime Ca(OH)2

Molecular Weight 74.09 g/mol

Component Compounds CID 962 (Water) CID 5460341 (Calcium)

Explanation:

8 0
3 years ago
Similarities of ancient and modern philosophy​
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A big difference is that for the Greeks philosophy was almost a fresh start. For us, doing philosophy cannot avoid taking into consideration what the great thinkers of the past have thought (or how they have thought).
7 0
3 years ago
3. A student adds 0.400g of n-propanol to 13.0 g of t-butanol. What is the molality of the solution? Show your calculations. (3
marissa [1.9K]

Answer:

m=0.512m

Explanation:

Hello,

In this case, we can consider the n-propanol as the solute (lower amount) and the t-butanol as the solvent (higher amount), for which, initially, we must compute the moles of n-propanol (molar mass = 60.1 g/mol) as shown below:

n_{solute}=0.400g*\frac{1mol}{60.1g0}=6.656x10^{-3}mol

Since the molality is computed via:

m=\frac{n_{solute}}{m_{solvent}}

Whereas the mass of the solvent is used in kilograms (0.0130g for the given one). Thus, we compute the resulting molality of the solution:

m=\frac{6.656x10^{-3}mol}{0.0130kg}\\ \\m=0.512\frac{mol}{kg}

Or just:

m=0.512m

Best regards.

8 0
3 years ago
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